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Artist 52 [7]
3 years ago
5

The aqueous equilibrium reaction below would not be affected by

Chemistry
1 answer:
german3 years ago
5 0

Answer:loko2020 I’m stupid I don’t know no answers sorry

Explanation:xd

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Write a transmutation nuclear equation that represents an example of fission
morpeh [17]

Answer:

²³⁸₉₂U →  ²³⁴₉₀Th  + ⁴₂He

Explanation:

Nuclei higher than Bi - 92 naturally are radioactive.

In a transmutation reaction, a new element is produced from an existing one due to radioactivity.

Nuclear fission is the radioactive process by which a heavy nucleus spontaneously decays into lighter ones with the release of a large amount of energy.

 One example is the transmutation of uranium into thorium;

         ²³⁸₉₂U →  ²³⁴₉₀Th  + ⁴₂He

 

4 0
3 years ago
Zeke is on spring break. He lives in a cold climate, so he decides to drive to a warmer climate. Before he leaves for his vacati
Pie
D.
This happens because in warmer temperatures, the atoms are more active. This increases the pressure because each atom uses up more space as they become more active.
7 0
3 years ago
Which tool is often fabricated on the job from small channel or angle iron
nadezda [96]

The answer is Straight Edge.

4 0
3 years ago
What is the wavelength, in nanometers, of light with a frequency of 5.89 x 10¹⁴ s⁻¹?
vovangra [49]

Answer:

<em><u>≅ 50, 909 nm</u></em>

Explanation:

Wavelength, λ = \frac{speed}{freq}

Given:

speed of light = 3*10^{8} m/s

f = 5.89 × 10^{14}

∴ λ = 3×10^{8} / 5.89 × 10^{14}

= 0.0000509 m <em><u>≅ 50, 909 nm</u></em>

<em><u /></em>

<em>Let me know if you need further assistance</em>

7 0
3 years ago
An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi
arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

             r = \frac{mv}{qB}

where,   m = mass,      v = velocity

              q = charge,    B = magnetic field

Therefore, q will be calculated as follows.

         q = \frac{mv}{rB}

            = \frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}

            = \frac{34.98 \times 10^{-22}}{0.01092}

            = 3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}

            = +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0
3 years ago
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