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Lemur [1.5K]
3 years ago
11

A moving roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it

reaches a velocity of 35\,\dfrac{\text{m}}{\text{s}}35 s m ​ 35, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. During this time, the roller coaster travels 41\,\text{m}41m41, start text, m, end text. We want to find the initial velocity of the roller coaster before it starts to accelerate. Which kinematic formula would be most useful to solve for the target unknown?
Physics
1 answer:
Ad libitum [116K]3 years ago
7 0

Answer:

Δx=(v+v0/2)t

Explanation:

We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.

In this problem, the target unknown is the initial velocity v_0v  

0

​  

v, start subscript, 0, end subscript of the roller coaster.

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A golf ball is struck at 75 m/s at an angle of 60 degrees. What is the
Gnesinka [82]

Answer:

v_x=37.50

Explanation:

The rectangular components of a vector \vec v having a magnitude v and angle θ are:

v_x=v\cos\theta

v_y=v\sin\theta

The golf ball has an initial speed of 75 m/s at an angle of 60 degrees.

The variables of the equations have the values:

v = 75 m/s

θ = 60°

Substituting into the formula:

v_x=75\cos 60^\circ

v_x=75\cdot 0.5

v_x=37.5~m/s

Without specifying units and with precision to the hundredths place:

\mathbf{v_x=37.50}

7 0
3 years ago
Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl
ladessa [460]

Answer:

The frequency of these waves is 4.27\times10^{-2}\ Hz

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

v = \dfrac{D}{T}

Where, D = distance

T = time

Put the value into the formula

v =\dfrac{8810}{8.67}

v=1016\ km/hr

We need to calculate the frequency

Using formula of frequency

v=n\lambda

n=\dfrac{v}{\lambda}

Put the value into the formula

n=\dfrac{1016}{6.6}

n=153.93\ hr

n=\dfrac{153.93}{60\times60}

n=0.0427\ Hz

n=4.27\times10^{-2}\ Hz

Hence, The frequency of these waves is 4.27\times10^{-2}\ Hz

8 0
3 years ago
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