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4 years ago

State thermodyNamic

Chemistry

2 answers:

Dovator [93]4 years ago

8 0

Answer:

thermodynamic deals with the heat and temperature and their relationship with energy

Explanation:

i hope this will help you

NARA [144]4 years ago

7 0

Answer: I Hope It Helps :)

The First Law of Thermodynamics (Conservation) states that energy is always conserved, it cannot be created or destroyed. In essence, energy can be converted from one form into another.
The third law of thermodynamics states that the entropy of a system at absolute zero is a well-defined constant.
The Second Law of Thermodynamics says that processes that involve the transfer or conversion of heat energy are irreversible

The fourth law of thermodynamics is the conservation of time

Explanation:

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Gerry is looking at salt under a powerful microscope and notices a crystalline structure. What can be known about

Allushta [10]

Answer:

The atoms are vibrating in place.

Explanation:

One of the properties of an ionic substance is the possession of a crystalline structure. As Gerry observed the salt under a microscope, he discovered that it has a crystalline structure. Crystalline salts are all ionic in nature, hence the salt observed by Gerry is an ionic salt.

Solids containing a definite crystalline structure always has their particles vibrating in place. This is immediately evident as Gerry looks at the salt through a microscope.

7 0

4 years ago

4. Suppose 8.00 g of CH4 is allowed to burn in the presence of 16.00 g of oxygen. CH4(g)+2O2(g)-->CO2(g)+2H2O(g)

umka21 [38]

<h3>Answer:</h3>

No masses of CH₄ and O₂ remained after the reaction, while 22.005 g of CO₂ and 18.02 g of H₂O remained

<h3>Explanation:</h3>

The combustion of methane is given by the reaction;

CH₄(g)+2O₂(g) → CO₂(g)+2H₂O(g)

We are given, 8 g of CH₄ and 16.00 g of O₂

Required to determine the mass of CH₄, O₂, CO₂ and H₂O that remained after the complete reaction.

<h3>Step 1: Moles of CH₄ and O₂ in the mass given </h3>

Moles = mass ÷ molar mass

Molar mass of CH₄ = 16.04 g/mol

Moles of CH₄ = 8.00 g ÷ 16.04 g/mol

= 0.498 moles

= 0.5 moles

Molar mass of O₂ = 16.0 g/mol

Moles of O₂ = 16.00 g ÷ 16.00 g/mol

= 1 mole

From the reaction, 1 mole of CH₄ reacts with 2 moles of O₂

CH₄ is the limiting reactant since it is way less than the amount of O₂

Therefore, 0.5 moles of CH₄ will react with 1 mole of oxygen.

This means there will be no amount of O₂ and CH₄ that remains.

<h3>Step 2: Moles of CO₂ and H₂O that were produced.</h3>

From the reaction 1 mole of CH₄ reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O.

Therefore,

In our case, 0.5 moles of CH₄ will react with 1 mole of O₂ to produce 0.5 moles of CO₂ and 1 mole of H₂O.

<h3>Step 3: Mass of CO₂ and H₂O produced </h3>

Mass = Moles × Molar mass

Molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.5 mol × 44.01 g/mol

= 22.005 g

Molar mass of H₂O = 18.02 g/mol

Moles of H₂O = 1 mole × 18.02 g/mol

= 18.02 g

Therefore, no masses of CH₄ and O₂ remained after the reaction, 22.005 g of CO₂ and 18.02 g of H₂O remained

3 0

4 years ago

Read 2 more answers

What are the 3 types of minerals?

Sunny_sXe [5.5K]

Answer:

1: quartz

2: feldspar

3: mica

Explanation:

5 0

4 years ago

why is it necessary to adjust the height of the graduated cylinder when measuring the volume of co2 (g) produced? group of answe

Elanso [62]

3. The height of the graduated cylinder when measuring the volume of co2 (g) produced is adjusted to equalize the pressure in the graduated cylinder with the atmospheric pressure.

We discovered that when the water level within the graduated cylinder is higher than the water level outside, the gases inside the graduated cylinder have a lower pressure than the atmospheric pressure. It would then be possible to equalize pressure by changing the graduated cylinder's water level to match the water level outside.

Therefore last option or 3rd option is the correct choice.

For more questions like Cylinder click the link below:

brainly.com/question/14085192

#SPJ4

5 0

1 year ago

The density of pure copper is 8.96 at 20°C. If 5.00 g of pure copper pellets is added to a graduated cylinder containing 14.6 mL

Triss [41]

Answer:

15.2 mL

Explanation:

First we calculate the volume of the copper

$volume = \frac{mass}{density}= \frac{5.00 g}{8.96 g/mL} = 0.5580 mL\\$

when this volume of copper is added to the water, the water level will rise by the level of the volume of copper. So the final volume is:

14.6 mL + 0.5580 mL = 15.158 mL

Since the measuring cylinder is graduated to one decimal place , we can round this up to 15.2 mL

8 0

3 years ago

State thermodyNamic​

State thermodyNamic