Answer:
diameter of transmission is 3.473 mm
Explanation:
given data
current = 300 A
total wire length = 1.0 m
voltage drop = 0.55 V
solution
as here Resistivity of copper is = 1.68 ×
ohm- m
so we get here resistance of wire that is
resistance =
..............1
R =
R = 1.774 ×
ohm
and now we get diameter of wire that is
R =
.............2
d² =
...............3
put here value
d² =
d =
d = 3.473 ×
m
d = 3.473 mm
so diameter of transmission is 3.473 mm
Answer:
53.36 m.
Explanation:
Initial velocity of the toolbox u = 0
acceleration due to gravity g = 9.8 m s⁻²
time t = 3.3 s
height of roof h = ?
h = ut + 1/2 g t²
= 0 + .5 x 9.8 x 3.3²
= 53.36 m.
Answer:
v = 8.90 km/h
Explanation:
In order to calculate the maximum collision speed of the 1200kg car, you take into account that the the kinetic energy of the car when it has a speed v, is equal to the potential elastic energy of the spring when it is maximum compressed.
Then, you use the following equation:
(1)
M: mass of the car = 1200kg
v: maximum collision speed of the car = ?
k: spring constant = 1.5MN/m = 1.5*10^6 N/m
x: maximum compression supported by the spring = 7.0cm = 0.070m
You solve the equation (1) for v and replace the values of the other parameters:
![v=x\sqrt{\frac{k}{M}}=(0.07m)\sqrt{\frac{1.5*10^6N/m}{1200kg}}\\\\v=2.47\frac{m}{s}](https://tex.z-dn.net/?f=v%3Dx%5Csqrt%7B%5Cfrac%7Bk%7D%7BM%7D%7D%3D%280.07m%29%5Csqrt%7B%5Cfrac%7B1.5%2A10%5E6N%2Fm%7D%7B1200kg%7D%7D%5C%5C%5C%5Cv%3D2.47%5Cfrac%7Bm%7D%7Bs%7D)
In km/h you obtain:
![v=2.47\frac{m}{s}*\frac{1km}{1000m}*\frac{3600s}{1\ h}=8.90\frac{km}{h}](https://tex.z-dn.net/?f=v%3D2.47%5Cfrac%7Bm%7D%7Bs%7D%2A%5Cfrac%7B1km%7D%7B1000m%7D%2A%5Cfrac%7B3600s%7D%7B1%5C%20h%7D%3D8.90%5Cfrac%7Bkm%7D%7Bh%7D)
The maximum collision that the car can support is 8.90km/h
Explanation:
If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.
Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.
Answer:
amount of work done = -1.77 J
Explanation:
given data
mass = 0.25 kg
speed = 5 m/s
height = 2m
to find out
amount of work done by the water on the ball bearing
solution
we get here potential energy when ball fall
potential energy = mgh
potential energy = 0.25 × 9.8 × 2
potential energy = 4.9 J
and that lose potential energy gain by kinetic energy that is express as
kinetic energy = 0.5 × m × v²
kinetic energy = 0.5 × 0.25 × 5²
kinetic energy = 3.13 J
so we get now work done that is
work done = kinetic energy - potential energy
work done = 3.13 J - 4.9 J
amount of work done = -1.77 J