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padilas [110]
3 years ago
8

Which object would have a LARGER gravitational force acting upon it? (assume the objects are at the same height above the Earth.

)
A) 5 kg block of wood
B) 100 kg person
C) 412 kg motorcycle
D) 2540 kg elephant
Physics
2 answers:
juin [17]3 years ago
3 0
It would be D because there is more gravitational forces acting on it than a small block of wood 
Juli2301 [7.4K]3 years ago
3 0

If the objects are all at the same distance from the center
of the Earth, then the gravitational forces between the Earth
and each object only depend on the mass of each object. 
Those forces are least for the 5kg object, and greatest for
the 2,540kg object. 

The gravitational force that attracts each object toward the
center of the Earth is typically referred to as the object's "weight".

It's important to know that there's another force of gravity ... the one
that attracts the Earth toward the object.  And that one is equal to
the object's weight, but pulls in the opposite direction.

Your weight on the Earth is equal to the Earth's weight on you.

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lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F_{mg}^> | = I(B^> × L^> )

given that

I = 2.6 A

B^> = 0.17

L^> = 0.52

so we substitute

|F_{mg}^> | = 2.6( 0.17i" × 0.52j" )

|F_{mg}^> | = 0.2298 N

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3 years ago
Can someone please help me?
Alina [70]

Answer:

D would be it

Explanation:

cause none of the rest Makes sense to the book of the picture and I'm 100% sure =)

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You are using a hydrogen discharge tube and high quality red and blue light filters as the light source for a Michelson interfer
boyakko [2]

Answer:

final displacement = +24484.5 nm

Explanation:

The path difference when 158 bright spots were observed with red light (λ1 = 656.3 nm) is given as;

Δr = 2d2 - 2d1 = 150λ1

So, 2d2 - 2d1 = 150λ1

Dividing both sides by 2 to get;

d2 - d1 = 75λ1 - - - - eq1

Where;

d1 = distance between the fixed mirror and the beam splitter

d2 = position of moveable mirror from splitter when 158 bright spots are observed

Now, the path difference between the two waves when 114 bright spots were observed is;

Δr = 2d'2 - 2d1 = 114λ1

2d'2 - 2d1 = 114λ1

Divide both sides by 2 to get;

d'2 - d1 = 57λ1

Where;

d'2 is the new position of the movable mirror from the splitter

Now, the displacement of the moveable mirror is (d2 - d'2). To get this, we will subtract eq2 from eq1.

(d2 - d1) - (d'2 - d1) = 75λ1 - 57λ2

d2 - d1 - d'2 + d1 = 75λ1 - 57λ2

d2 - d'2 = 75λ1 - 57λ2

We are given;

(λ1 = 656.3 nm) and λ2 = 434.0 nm.

Thus;

d2 - d'2 = 75(656.3) - 57(434)

d2 - d'2 = +24484.5 nm

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