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padilas [110]
3 years ago
8

Which object would have a LARGER gravitational force acting upon it? (assume the objects are at the same height above the Earth.

)
A) 5 kg block of wood
B) 100 kg person
C) 412 kg motorcycle
D) 2540 kg elephant
Physics
2 answers:
juin [17]3 years ago
3 0
It would be D because there is more gravitational forces acting on it than a small block of wood 
Juli2301 [7.4K]3 years ago
3 0

If the objects are all at the same distance from the center
of the Earth, then the gravitational forces between the Earth
and each object only depend on the mass of each object. 
Those forces are least for the 5kg object, and greatest for
the 2,540kg object. 

The gravitational force that attracts each object toward the
center of the Earth is typically referred to as the object's "weight".

It's important to know that there's another force of gravity ... the one
that attracts the Earth toward the object.  And that one is equal to
the object's weight, but pulls in the opposite direction.

Your weight on the Earth is equal to the Earth's weight on you.

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photoshop1234 [79]
The answer would be C (the one you picked)

Hope this helps

Have a great day/night
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Explanation:

See attachment

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marta [7]

Answer:

Explanation:

Given

height from which ball is dropped h_1=9.5\ m

and it rises to a height of h_2=5.7\ m

A person caught the ball in mid-way i.e. at a height of h_0=1.2\ m from pavement

time taken to reach the bottom is given by

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

here initial velocity is zero i.e.

h_1=0+\frac{1}{2}gt_1^2

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Similarly to reach of  height h_2 time taken is t_2

t_2=\sqrt{\frac{2h_2}{g}}

The ball is caught in mid-way i.e. ball travel a distance of h_3=5.7-1.2=4.5\ m

time taken is t_3=\sqrt{\frac{2h_3}{g}}

total time taken t=t_1+t_2+t_3

t=\sqrt{\frac{2h_1}{g}}+\sqrt{\frac{2h_2}{g}}+\sqrt{\frac{2h_3}{g}}

t=\sqrt{\frac{2\cdot 9.5}{9.8}}+\sqrt{\frac{2\cdot 5.7}{9.8}}+\sqrt{\frac{2\cdot 4.5}{9.8}}

t=3.429\ s

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4 0
3 years ago
The pressure of a liquid is given by P = pgh. Calculate the pressure (in SI unit) if the
BlackZzzverrR [31]

Answer:

5000 Pa

Explanation:

First collect the data you've been given already and make sure to convert into the right units;

<em>Density</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>g</em><em>/</em><em>cm³</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>Kg</em><em>/</em><em> </em><em>m³</em>

<em>acceleration</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>gravity</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>m</em><em>/</em><em>s²</em>

<em>Height</em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em> </em><em>cm</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>0</em><em>.</em><em>5</em><em> </em><em>m</em>

after collecting the data, use the formula to solve

<em>pressure</em><em> </em><em>=</em><em> </em><em>pgh</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em>0</em><em>0</em><em> </em><em>Pa</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

6 0
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Verdich [7]

Answer:

Los fusibles están diseñados de tal forma que estos se "rompen" o se funden, cuando la demanda eléctrica supera un dado valor (cuando demasiada electricidad pasa a través de el).

Una vez el filamento se rompe, la corriente ya no puede circular por el (podes pensar en esta situación como un cable roto, la electricidad no puede circular por este cable)

Entonces, al romperse el filamento, en caso de una sobrecarga eléctrica, el flujo de electricidad se corta, y de esta forma se protege al computador de posibles sobrecargas.

4 0
3 years ago
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