Question

a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas if the pressure is reduced to 200.0mm Hg at constant temperature?

Answer 1

Answer:

1200 mL

Explanation:

Given data

• Initial pressure (P₁): 600.0 mmHg

• Initial volume (V₁): 400.0 mL

• Final pressure (P₂): 200.0 mmHg

• Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

$P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL$