Answer:
The magnetic field will be , '2d' being the distance the wires.
Explanation:
From Biot-Savart's law, the magnetic field () at a distance '' due to a current carrying conductor carrying current '' is given by
where '' is an elemental length along the direction of the current flow through the conductor.
Using this law, the magnetic field due to straight current carrying conductor having current '', at a distance '' is given by
According to the figure if '' be the current carried by the top wire, '' be the current carried by the bottom wire and '' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by symbol.
Given and
Therefore, the magnetic field () at 'P' due to the top wire
and the magnetic field () at 'P' due to the bottom wire
Therefore taking the value of the net magnetic field () at the midway between the wires will be
Airplanes produce lift from the air moving over their wings. Stall speed is a metric that refers to the minimum speed required for an airplane to produce lift. When airplanes fly slower than their respective stall speed, they won't produce lift. ... If an airplane's speed drops below its stall speed, it won't produce lift.
Answer:
A) True, B) False, C) False and D) false
Explanation:
Let's solve the problem using the law of conservation of energy to know if the statements are true or false
Let's look for mechanical energy
Initial
Emo = Ke = ½ k Dx2
Final
Em1= ½ m v12
Emo = Em1
½ k Δx2 = ½ m v₁²
v₁² = k / m Δx²
v₁ = √ k/m Δx
Now let's calculate the speed when it falls
Vfy² = Voy² - 2gy
Vfy² = - 2gy
Vf² = v₁² + vfy²
A) True v₁ = A Δx
.B) False. As there is no rubbing the mechanical energy conserves
.C) False the velocity is proportional to the square root of the height
v2y = v2 √2
. D) false promotional compression speed
It acquires a positive electric charge.
C, at this moment it is directly 90 degrees to the right and is only travelling downwards