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Charra [1.4K]
3 years ago
15

What's the population of people with six packs

Physics
1 answer:
Iteru [2.4K]3 years ago
5 0
About half of the people mostly MEN..?
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Which is not a way to accelerate an object?
densk [106]
I would definitely think its B....
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3 years ago
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A disk-shaped platform has a known rotational inertia ID. The platform is mounted on a fixed axle and rotates in a horizontal pl
Zarrin [17]

Answer:

Explanation:

The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.

 \mathbf{I_w} = constant.

The overall value of such moment of inertia is now altered when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.

Recall that:

The Kinetic energy is given by:

\mathbf{K = \dfrac{1}{2} Iw^2} \\ \\\mathbf{K = \dfrac{1}{2} lw*w}

where;

\mathbf{I_w} is constant and w reduces;

As a result, just after the collision, the system's total kinetic energy decreases.

5 0
3 years ago
Fe has the electron configuration [Ar]3d64s2. What is the magnitude of the orbital angular momentum for its most energetic elect
salantis [7]

Answer : The magnitude of the orbital angular momentum for its most energetic electron is, \sqrt{6}\hbar

Explanation :

The formula used for orbital angular momentum is:

L=\sqrt{l(l+1)}\hbar

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is, [Ar]3d^64s^2

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

L=\sqrt{2(2+1)}\hbar

L=\sqrt{6}\hbar

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is, \sqrt{6}\hbar

7 0
3 years ago
What expression gives the amount of light energy (in J per photon) that is converted to other forms between the fluorescence exc
erastovalidia [21]

Answer:

E = hf or E=\dfrac{hc}{\lambda}

Explanation:

The expression that gives the amount of light energy that is converted to other forms between the fluorescence excitation and emission events is given by :

E = hf

f is the frequency

E=\dfrac{hc}{\lambda}

c is the speed of light

\lambda is the wavelength

Hence, this is the required solution.

8 0
3 years ago
Why are electromagnets, rather than permanent magnets, used in MRLs?
yKpoI14uk [10]

Answer:

The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.

Explanation:

5 0
4 years ago
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