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3 years ago

11

How much work is requried to uniformly accelerate a merry-go-round?

1 answer:

tiny-mole [99]3 years ago

5 0

Do not worry if you don't recognize both parts of the problem at this point. If you recognize the dynamics problem,<span> On the other hand, if you recognize this as a kinematics problem you will quickly see that you need to find angular acceleration before you can begin and so will need to do that pre-step first.</span>

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"An object weighing 10.01 grams is placed in a graduated cylinder containing 3.90 mL of water. If the total volume of the object

Alex73 [517]

Answer:

Density of the object = 1.9399g/mL

Explanation:

Mass of object = 10.01g

Volume of water = 3.90mL

Volume of Object + Water = 9.06mL

Therefore, volume of Object = Volume of Object + Water - Volume of Water

= 9.06mL - 3.90mL

= 5.16mL

Density by definition is the mass per unit volume of a substance.

Density of the object = mass/volume

= 10.01/5.16

= 1.9399g/mL or 1.94kg/m3

8 0

2 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.59 times a second. A tack is stuck in the tire a

Vesna [10]

Answer:

Tangential speed=5.4 m/s

Radial acceleration= $88.6m/s^2$

Explanation:

We are given that

Angular speed=2.59 rev/s

We know that

1 revolution= $2\pi rad$

2.59 rev= $2\pi\times 2.59=5.18\pi=5.18\times 3.14=16.27 rad/s$

By using $\pi=3.14$

Angular velocity= $\omega=16.27rad/s$

Distance from axis=r=0.329 m

Tangential speed= $r\omega=16.27\times 0.329=5.4m/s$

Radial acceleration= $\frac{v^2}{r}$

Radial acceleration= $\frac{(5.4)^2}{0.329}=88.6m/s^2$

6 0

3 years ago

A skateboarder shoots off a ramp with a velocity of 7.1 m/s, directed at an angle of 61° above the horizontal. The end of the ra

dsp73

Answer:

Highest point reached = 3.37 m

Explanation:

Initial velocity, = 7.1 m/s

Initial vertical velocity = 7.1 sin 61 = 6.21 m/s

Consider the vertical motion of skateboarder,

We have equation of motion, v² = u² + 2as

Initial velocity, u = 6.21 m/s

Acceleration, a = -9.81 m/s²

Final velocity, v = 0 m/s

Substituting

v² = u² + 2as

0² = 6.21² + 2 x -9.81 x s

s = 1.97 m

So from ramp the position it goes up by 1.97 m

Highest point reached = 1.97 + 1.4 = 3.37 m

6 0

2 years ago

which statement best describes how changes behave a.opposites charges repel against each other and like charges attract to each

Anon25 [30]

I think it is B hope this helps

God Bless

7 0

2 years ago

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natima [27]

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5 0

2 years ago