When light, starting in air, is shone on a piece of glass, what effects are you likely to observe? a. reflection b. refraction 3
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In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.
Part a)
when we pull the rod with constant speed then power required will be product of force and velocity
here we will have
P = 4 W
v = 4 m/s
now we will have
So external force required will be 1 N
PART B)
now in order to find magnetic field strength we can say
here we know that induced EMF in the wire is E = vBL
so power due to induced magnetic field is given by
by solving above equation we will have