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scoundrel [369]
3 years ago
8

If the function m(x) has the point (5, 2) on its graph name a point that would be on the function m(5x).

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

21

Step-by-step explanation:

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Which of the following inverse functions are defined for x=-1/2? Select all that apply.
Aleksandr-060686 [28]

Answer:

A, B, E, and F  

Step-by-step explanation:

sinx and cosx are defined for all values of x. So, sin⁻¹x and cos⁻¹x  are also defined for all values of x.  

A and E are correct.

tanx is defined for all values of x.

However, tan(nπ) = 0 at when n is an integer. So, tan⁻¹(±nx) is undefined. However, tan⁻¹(-½x) is defined, because -½ is not an integer.

B and F are correct.

C and D are <em>wrong</em>. Both sec⁻¹x  and csc⁻¹x are undefined when -1 < x < 1, and -½ is in this forbidden region.

4 0
3 years ago
Find the solution of this system of equations shown on the graph.
elena-s [515]
Answer is (0,3)

hope it helps
3 0
3 years ago
How to solve this :') please help
blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}

7 0
2 years ago
A satellite orbits Earth at a rate of about 3,300 miles in 12 minutes. At this​ rate, how far does the satellite travel around E
Vaselesa [24]
16,500

60 minutes in an hour / 12 minutes = 5
5 * 3,300 = 16,500
7 0
3 years ago
Read 2 more answers
Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x2 – 36X?
Fiesta28 [93]
Assuming I understand your question correctly, in that you’re looking for just some descriptions of the differences between the functions. If so, then I’d say:

First graph both functions, the f(x) and the g(x). Then spot the differences.
Note that the g(x) function has shifted towards the right compared with the f(x) function.
Another way that the g(x) differs from the f(x) function is that it’s stretched. The vertex is in the IV quadrant for g(x) rather than at the origin for f(x).

I hope that helps.

5 0
3 years ago
Read 2 more answers
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