Answer:
a) the force goes down, b) The electric force is out of the screen
c) the force is zero
Explanation:
To determine the direction of a magnetic force we use the right hand rule. For a positive charge, the thumb is in the direction of speed, the fingers extended in the direction of the magnetic field, and the palm points in the direction of force. Let's apply this to our case
a) thumb to the right
Fingers spread out
And the force goes down
b) the electric force in the direction of the electric field if the charge is positive
Positive charge
Electric field out of the screen
The electric force is out of the screen
c) charge moving out screen
Magnetic field entered on the screen
Since they are parallel, therefore the force is zero
Answer:Red has the longest wavelength and violet has the shortest wavelength. When all the waves are seen together, they make white light. Ultraviolet (UV) light—is radiation with a wavelength shorter than that of visible light, but longer than X-rays, in the range 10 nm to 400 .
Explanation:
Answer:
a) v = 54.7m/s
b) v = (58 - 1.66a) m/s
c) t = 69.9 s
d) v = -58.0 m/s
Explanation:
Given;
The height equation of the arrow;
H = 58t - 0.83t^2
(a) Find the velocity of the arrow after two seconds. m/s;
The velocity of the arrow v can be given as dH/dt, the change in height per unit time.
v = dH/dt = 58 - 2(0.83t) ......1
At t = 2 seconds
v = dH/dt = 58 - 2(0.83×2)
v = 54.7m/s
(b) Find the velocity of the arrow when t = a. m/s
Substituting t = a into equation 1
v = 58 - 2(0.83×a)
v = (58 - 1.66a) m/s
(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s
the time when H = 0
Substituting H = 0, we have;
H = 58t - 0.83t^2 = 0
0.83t^2 = 58t
0.83t = 58
t = 58/0.83
t = 69.9 s
(d) With what velocity will the arrow hit the surface? m/s
from equation 1;
v = dH/dt = 58 - 2(0.83t)
Substituting t = 69.9s
v = 58 - 2(0.83×69.9)
v = -58.0 m/s
The pressure at the depth h in the ocean is given by (Stevin's law)
where
is the atmospheric pressure
and
is the pressure exerted by the column of water of height h=4267 m, with
being the water density and
.
Substituting, we find
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so
, therefore we just need to divide by this number: