Voltmeter is used to find the potential difference between two points.
We always connect it in parallel to the points where we need the potential difference.
Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.
Answer:
<em>Well, I think the best answer will be is </em><em>1.59 g/mL Good Luck!</em>
Answer:

between the plates.
Explanation:
The equation for change of voltage between two points separated a distance d inside parallel conducting plates (<em>which have between them constant electric field</em>) is:

So to calculate our electric field strength we use the fact that the potential 8.8 cm from the zero volt plate is 475 V:

And we use the fact that the plates are 9.2cm apart to calculate the voltage between them:

Answer:
In free fall, mass is not relevant and there's no air resistance, so the acceleration the object is experimenting will be equal to the gravity exerted. If the object is falling on our planet, the value of gravity is approximately 9.81ms2 .