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ludmilkaskok [199]
3 years ago
12

Solar energy breaks oxygen molecules apart in the stratosphere, releasing ____, which combine(s) with additional oxygen molecule

s to form ____.
Physics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

Oxygen atom

Ozone Molecule

Explanation:

The upper stratosphere and Mesosphere consist of the ozone layer. This layer helps in protecting us from the UV radiations of the Sun. This layer converts the UV radiation into heat energy.

The UV radiation breaks down the Oxygen molecules in oxygen atom which further combines with oxygen molecule to form Ozone. This Ozone molecule breaks to form Oxygen atom and Oxygen molecule. Oxygen atom further recombines with Oxygen molecule to make Ozone molecule. This is known as Ozone-Oxygen cycle. The excess energy is released as heat.

Everyday around 400 million metric tons of Ozone is produced through this cycle.

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A symbolic model for learning is a model that is observed in person.
kap26 [50]

Answer:

True

Explanation:

3 0
3 years ago
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A 60 kg runner accelerates during a race at 3m/s2. what force is exerted on the earth with each step
marusya05 [52]

Answer:

180 Newton(N)

Explanation:

force =mass *acceleration

=60 * 3

=180 kgm/s^2

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6 0
3 years ago
If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.
grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution.  By definition is defined as:

\theta = 1.22\frac{\lambda}{d}

Where,

\lambda= Wavelength

d = Width of the slit

\theta= Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

r = l\theta

Relacing \theta

r = l(\frac{1.22\lambda}{d})

r = 1.22\frac{l\lambda}{d}

Replacing with our values we have that,

r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})

r = 3680.91m

Therefore the diameter of the beam on the moon is

d = 2r

d = 2 * (3690.91)

d = 7361.8285m

Hence, the diameter of the beam when it reaches the moon is 7361.82m

8 0
3 years ago
What benefits does preforming this investigation in the physical world have over the computer simulation?
mezya [45]

Explanation:

Can be safer and cheaper than the real world. Able to test a product or system works before building it. Can use it to find unexpected problems. Can speed things up or slow them down to see changes over long or short periods of time.

.

.

.

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3 0
3 years ago
A car traveling at 50 m/s comes to a stop in 5 seconds. What is the<br> acceleration of this car?
Alexandra [31]

Answer:10

Explanation:

You have to do speed divided by time so your answers 10

4 0
2 years ago
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