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3 years ago

What are some physical activities you can do at home to help you with arm strength , as well as

Physics

1 answer:

Bond [772]3 years ago

6 0

Answer:

See the explanation below

Explanation:

To improve the strength in the arms can be performed arm push-ups, there are different variants for this exercise. But ideally, perform the known basic exercise, try to touch with the chest the floor and then rise up to the length of the arms using the strength of these. It will be necessary for beginners to perform a routine of 3 sets to 10 repetitions. Rest one day. In the third week you can perform 4 sets to 25 repetitions, resting only one day. This will improve the strength in the arms considerably.

For the legs should stimulate the muscle of the quadriceps, should perform an exercise known as squat, to perform it should be lowered with your back straight until the knees form an angle of 90 degrees, for beginners should perform 3 sets of 15 repetitions a day, resting only one day. In the second week you can perform 4 sets of 25 repetitions a day, resting one day a week.

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A diffraction grating with 1000 lines per mm is used in a spectrometer to measure the wavelengths of light emitted from a gas di

frez [133]

Answer:

= 9.8°

Explanation:

Width of one slit (a₁ ) = 1 / 1000 mm=0.001 mm = 10⁻⁶ m.

width of one slit in case 2 (a₂ ) = 1/500 =2 x 10⁻⁶ m

angular position of fringe, Sinθ = n λ /a

n is order of fringe , λ is wave length of light and a is slit aperture

So Sinθ ∝ 1 / a

Sin θ₁ /Sin θ₂ = a₂/a₁ ;

Sin20°/sinθ₂ = 2 / 1

sinθ₂ = Sin 20° / 2 = .342/2 = .171

θ₂ = 9.8 °

4 0

3 years ago

How do I calculate (30 points plus a brainlyest if correct)

Nat2105 [25]

Answer:

Are you trying to calculate the net force?

If so, it would be 3 N Up.

This is because the 15 N forces from the left and right cancel out, leaving only the upwards 15 N force, and the 12 N force. However, we have to subtract 12 from 15, leaving the final net force to be 3 N Up.

Let me know if this helps!

3 0

3 years ago

A bicycle with an initial velocity of +6 m/s accelerates at a

patriot [66]

Answer :
It covers 27 meters

5 0

4 years ago

True or False. If statement is false, change the word in parentheses to make it true.

xz_007 [3.2K]

False

Explanation:

Loudness is the human perception of sound intensity and not pitch. Pitch is a property of waves.

Loudness measures the intensity of sound to the hear and the frequency is often expressed in decibels.

Pitch is how high or low a note is being played.
It is a property that makes it to judge whether sounds are high or low.
Loudness on the other hand is depends on the human perception of how high or low sound is to a person.

learn more:

Amplitude of sound waves brainly.com/question/2845448

#learnwithBrainly

6 0

3 years ago

Given two objects of the same mass but of different sizes, which object has a greater density?

wolverine [178]

Given two objects of the same mass but of different sizes, the one that has a greater density is: a. the smaller object

Due to the density of an object is the relation that exist between the mass and the space that the object occupies, if we have two objects with the same mass the one that is going to have a greater density is the smaller object because it occupies less space with more mass.

We can prove it using the density formula to solve the following exercise:

Two objects have a mass of 100 g, and their volume are 20 cm³ and 10 cm³ respectively, what is the density of each one?

The general formula of the density is:

d = m/v

Where:

d= density
m= mass
v= volume

Information about the problem:

m = 100 g
v1= 20 cm³
v2=10 cm³
d1=?
d2?

Applying the density formula we get:

d = m/v

d1 = 100g/20 cm³

d1 = 5g/cm³

d2 = 100g/10 cm³

d2 = 10g/cm³

With the results we can confirm that the object that has the greater density is the smaller, because it has less volume.

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

4 0

1 year ago