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mixas84 [53]
3 years ago
10

A 40-kg uniform semicircular sign 1.6 m in diameter is supported by two wires as shown. What

Physics
1 answer:
garri49 [273]3 years ago
4 0

Answer:

T1 = 131.4 [N]

T2 = 261 [N]

Explanation:

To solve this problem we must make a sketch of how will be the semicircle, for this reason we conducted an internet search, to find the scheme of the problem. This scheme is attached in the first image.

Then we make a free body diagram, with this free body diagram, we raise the forces that act on the body. Since it is a problem involving static equilibrium, the sum of forces in any direction and moments must be equal to zero.

By performing a sum of forces on the Y axis equal to zero we can find an equation that relates the forces of tension T1 & T2.

The second equation can be determined by summing moments equal to zero, around the point of application of the T1 force. In this way we find the T2 force.

The value of T2, is replaced in the first equation and we can find the value for T1.

Therefore

T1 = 131.4 [N]

T2 = 261 [N]

The free body diagram and the developed equations can be seen in the second attached image.

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Two objects of equal mass are a fixed distance apart. If the mass of each object could be tripled, the gravitational force betwe
antiseptic1488 [7]

gravitational force between two objects is given as

F = G m₁ m₂/r²

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gravitational force between the objects is given as

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Final Case :

m₁ = m₂ = 3 m

new gravitational force between the objects is given as

F' = G (3m)²/r²

F' = 9 G m²/r²

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3 years ago
State an advantage of using such hydraulic jack to lift a load ​
expeople1 [14]

Answer:

Explanation:

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3 years ago
You've recently read about a chemical laser that generates a 20.0-cm-diameter, 26.0 MW laser beam. One day, after physics class,
aksik [14]

Answer :

(a). The speed of the block is 0.395 m/s.

(b). No

Explanation :

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Diameter = 20.0 cm

Power = 26.0 MW

Mass = 110 kg

diameter = 20.0 cm

Distance = 100 m

We need to calculate the pressure due to laser

Using formula of pressure

P_{r}=\dfrac{I}{c}

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P_{r}=2.75\ N/m^2

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a=\dfrac{0.086}{110}

a=0.000781\ m/s^2

a=7.81\times10^{-4}\ m/s^2

(a). We need to calculate speed of the block

Using equation of motion

v^2=u^2+2ad

Put the value into the formula

v=\sqrt{2\times7.81\times10^{-4}\times100}

v=0.395\ m/s

(b). No because the velocity is very less.

Hence, (a). The speed of the block is 0.395 m/s.

(b). No

8 0
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ser-zykov [4K]

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Explanation:

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