A 40-kg uniform semicircular sign 1.6 m in diameter is supported by two wires as shown. What
1 answer:
Answer:
T1 = 131.4 [N]
T2 = 261 [N]
Explanation:
To solve this problem we must make a sketch of how will be the semicircle, for this reason we conducted an internet search, to find the scheme of the problem. This scheme is attached in the first image.
Then we make a free body diagram, with this free body diagram, we raise the forces that act on the body. Since it is a problem involving static equilibrium, the sum of forces in any direction and moments must be equal to zero.
By performing a sum of forces on the Y axis equal to zero we can find an equation that relates the forces of tension T1 & T2.
The second equation can be determined by summing moments equal to zero, around the point of application of the T1 force. In this way we find the T2 force.
The value of T2, is replaced in the first equation and we can find the value for T1.
Therefore
T1 = 131.4 [N]
T2 = 261 [N]
The free body diagram and the developed equations can be seen in the second attached image.
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Answer:
the velocity (magnitude and direction) of the ball) just before the collision is
The velocity (magnitude and direction) of the ball) just after the collision is
Explanation:
According to the law of conservation of energy;
Thus; the velocity (magnitude and direction) of the ball) just before the collision is
Since, Air resistance is negligible, and the collision is elastic.
The equation for the conservation of momentum and energy can be expressed as:
The velocity (magnitude and direction) of the ball) just after the collision is