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3 years ago

How can one determine the median of a data set?

1 answer:

3 0

One can determine the median of a data set by ordering the data points and finding the middle value of the set. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has come to your desired help

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State the periodic table

kogti [31]

Answer:

Heres a picture of the periodic table.

Explanation:

Source(s):Science News for Students

5 0

3 years ago

Méthode pour sépare l'eau et vermiculite !

wolverine [178]

Answer:

Filtración

Explanation:

Cuando se filtra una mezcla de arena y agua, la vermiculita se queda en el papel de filtro y el agua gotea. Como un filtro de café.

8 0

2 years ago

If you have 10cm of snow with a volume of 40mL and a density of 0.5 g/mL how many inches of rain is this?

Lelu [443]

Density is the mass of compound divided by its volume can be shown as follows:

$d = 0.5 g /mL = m /V = m /40 = 0.5$

$m = 20 g$

40 mL of snow having 20 g of mass calculated from density.

Now, 10 cm of snow = 3.93 inches = 20 g

As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

10 inches rain = 11 inches snow

3.93 inches of snow produced by

$= (3.93 * 10) /11 = 3.57 inches rain.$

Thus, 3.57 incehs of rain produces by 10 cm snow.

4 0

3 years ago

The combining of hydrogen and oxygen gas into liquid water is an example of what kind of change?

KatRina [158]

The combining of hydrogen and oxygen gas into liquid=H2O (water) is a compound or a molecule because it is 2 different elements combined with chemical bonds so its Chemical. B

7 0

3 years ago

If the [H3O+] of a solution is 1x 10-8 mol/L the [OH-] is

Studentka2010 [4]

Answer:

Explanation:

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

1x 10-8 mol/L equals to1x10-8 M

(H3O+) x (OH-) = 1x10^-14

(H30+)x 1x 10^-8 =1x10^-14

(H30+)= 1x10^-14/1x 10^-8

6 0

3 years ago