Answer:
Q = 5350.2 Joules.
Explanation:
<u>Given the following data;</u>
Mass, m = 26. 5g
Initial temperature, T1 = 0°C
Final temperature, T2 = 48.3°C
Specific heat capacity of water, c = 4.18 J/g°C.
*To find the quantity of heat*
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 48.3 - 0
dt = 48.3°C
Substituting the values into the equation, we have;
Q = 5350.2 Joules.
Therefore, the amount of heat absorbed is 5350.2 Joules.
Answer is: the freezing point of the solution of sucrose is -0.435°C.
m(H₂O) = 100 g ÷ 1000 g/kg = 0.1 kg.
m(C₁₂H₂₂O₁₁) = 8.0 g.
n(C₁₂H₂₂O₁₁) = m(C₁₂H₂₂O₁₁) ÷ M(C₁₂H₂₂O₁₁).
n(C₁₂H₂₂O₁₁) = 8.0 g ÷ 342.3 g/mol.
n(C₁₂H₂₂O₁₁) = 0.0233 mol.
b(solution) = n(C₁₂H₂₂O₁₁) ÷ m(H₂O).
b(solution) = 0.0233 mol ÷ 0.1 kg.
b(solution) = 0.233 m.
ΔT = b(solution) · Kf(H₂O).
ΔT = 0.233 m · 1.86°C/m.
ΔT = 0.435°C.
Tb = 0°C - 0.435°C = -0.435°C.
Answer:
A Physical Model might include a drawing or a three-dimensional object.
Hope this helps ^^
Uhhh what is that! It looks hard!!!