Answer:
Baby are born due to the fertilization of Owen or egg present in vigina due to the fertilization from sperms
 
        
                    
             
        
        
        
Answer:
To write the general formula for an acid, we fix one atom which is hydrogen because this atom is common to all the acids. General formula for acid is written by HX. where H represents Hydrogen atom.
Explanation:
 
        
             
        
        
        
Answer:
Psm = 30.66 [Psig]
Explanation:
To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.
P * v = R * T
where:
P = pressure [Pa]
v = specific volume [m^3/kg]
R = gas constant for air = 0.287 [kJ/kg*K]
T = temperature [K]
<u>For the initial state</u>
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P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)
T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)
Therefore we can calculate the specific volume:
v1 = R*T1 / P1
v1 = (0.287 * 270.4) / 266.8
v1 = 0.29 [m^3/kg]
As there are no leaks, the mass and volume are conserved, so the volume in the initial state is equal to the volume in the final state.
V2 = 0.29 [m^3/kg], with this volume and the new temperature, we can calculate the new pressure.
T2 = 43 + 273 = 316 [K]
P2 = R*T2 / V2
P2 = (0.287 * 316) / 0.29
P2 = 312.73 [kPa]
Now calculating the manometric pressure
Psm = 312.73 -101.325 = 211.4 [kPa]
And converting this value to Psig
Psm = 30.66 [Psig]
 
        
             
        
        
        
Answer:
20.2 seconds
Explanation:
The airplane (and therefore the crate) initially has no vertical velocity, so v₀ = 0 m/s.
The crate is in free fall, so a = -9.8 m/s².
The crate falls downward, so Δx = -2000 m.
Find: t, the time it takes for the crate to land.
Δx = v₀ t + ½ at²
-2000 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 20.2 s
It takes 20.2 seconds for the crate to land.
 
        
             
        
        
        
Answer:
The final angular speed is 16.1 rad/s
Explanation:
Given;
initial moment of inertia, I₁ = 2.56 kg.m²
final moment of inertia, I₂ = 0.40 kg.m²
initial angular speed, ω₁ = 0.4 rev/s = 2.514 rad/s
Apply the principle of conservation of angular momentum;
I₁ω₁ = I₂ω₂
where;
ω₂ is the final angular speed
ω₂ = (I₁ω₁) / (I₂)
ω₂ = (2.56 x 2.514) / (0.4)
ω₂ = 16.1 rad/s
Therefore, the final angular speed is 16.1 rad/s