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3 years ago

If 7.35 L of gas at 17°C and 3.55 atm is compressed at a pressure of 123 atm and 34°C, calculate the

Chemistry

1 answer:

MaRussiya [10]3 years ago

6 0

Answer: V2= 0.224L

Explanation:

P1=3.55atm, V2= 7.35L, T1= 290, P2= 123atm, V2=?, T2= 307K

Applying general gas equation

P1V1/T1= P2V2/T2

Substitute and Simplify

3.55×7.35/290 = 123×V2/307

V2= 0.224L

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As NH4Cl dissolves in water, and cools the solution,

azamat

Answer:

d. delta H is positive, and delta S is positive

Explanation:

The process of dissolution of NH4Cl is:

NH4Cl(s) → NH4+(aq) + Cl-(aq)

As the solution is cooled, the process is absorbing energy, that means ΔH > 0. (ΔH < 0 when the heat is released).

As there are produced 2 ions from 1 solid molecule, the disorder is increasing and ΔS > 0

The right answer is:

<h3>d. delta H is positive, and delta S is positive</h3>

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3 years ago

Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te

yulyashka [42]

Answer:

$n_{N_2}=6.41mol$

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

$PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol$

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

$n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol$

Quiere decir que las moles de N2(g) que se agregaron son:

$n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol$

¡Saludos!

8 0

3 years ago

Identify the best practices when storing and using drying agents in the lab.

IrinaVladis [17]

Answer:

A. Close the drying agent container whenever it is not in active use.

C. Wrap the lid of the drying agent container with tape for storage.

Explanation:

Drying agents also known as desiccants are used in pharmaceutical, food and other manufacturing to keep substances dry. These drying agents are anhydrous and hygroscopic. The right usage of these products requires that they are always stored in an air-tight container.

When they are to be removed from a container containing a solvent, they are to be separated by filtration or decanting.

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3 years ago

Calculate the mass in grams of 1.72×10^24 molecules of formaldehyde. The chemical formula for formaldehyde is CH2O.

pishuonlain [190]

Answer: m= 85.8 g CH2O

Explanation: First step is convert the molecules of CH2O to moles using the Avogadro's Number.

1.72x10²⁴ molecules CH2O x 1 mole CH2O / 6.022x10²³ molecules CH2O

= 2.86 moles CH2O

Next is convert the moles of CH2O to mass using the molar mass of CH2O

2.86 moles CH2O x 30 g CH2O / 1 mole CH2O

= 85.8 g CH2O

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3 years ago

What is instantaneous acceleration?A. how fast a speed is changing at a specific instant B. how fast a velocity is changing at a

joja [24]

If i had to answer i would choose a hope this helps

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3 years ago