Answer:
The only oxidation- reduction reaction is <u>Cu (s) + 2AgNO3 (aq) → 2Ag (s) + Cu(NO3)2</u>
Explanation:
An oxidation-reduction reaction is a chemical reaction that involves an electron transfer between two species. This will lead to a change in oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
Some atoms have different possible oxidation numbers.
H has oxidation number +1
O has oxidation number -2
The oxidation number of an individual atom is 0.
The total oxidation number of all atoms in: a neutral species is 0 and in an ion is equal to the ion charge.
⇒ Ba(C2H3O2)2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaC2H3O2
(C2H3O2)2 has an oxidation number of -2. So Ba has an oxidation number of +2
In BaSO4 has SO4 an oxidation number of -2 and Ba has an oxidation number of +2
This means <u>Ba doesn't change its oxidation number.</u>
In Na2SO4 Na has an oxidation of +1; in NaC2H3O2 Na has an oxidation of +1
This means <u>Na doesn't change its oxidation number. </u>
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<u>⇒ Cu (s) + 2AgNO3 (aq) → 2Ag (s) + Cu(NO3)2</u>
Cu has an oxidation number of 0
In Cu(NO3)2, NO3 has an oxidation number of -1 so Cu has an oxidation number of +2
In 2AgNO3, NO3 has an oxidation number of -1 so Ag has an oxidation number of +1
Ag has an oxidation number of 0
⇒ HCl (aq) + NaOH (aq) → H2O (l) + NaCl
The oxidation number of Cl and Na do not change
⇒ AgNO3 (aq) + HCl (aq) → AgCl (s) + HNO3
In AgNO3 Ag has an oxidation number of +1
In AgCl Ag has an oxidation number of +1
In HCl Cl has an oxidation number of -1
In AgCl Cl has an oxidation number of +1
The oxidation number of Cl and Ag do not change
⇒ H2CO3 (aq) + Ca(NO3)2 (aq) → 2HNO3 (aq) + CaCO3 (s)
In Ca(NO3)2 Ca has an oxidation number of +2
In CaCO3 Ca has an oxidation number of +2
In Ca(NO3)2 N has an oxidation number of +5
In HNO3 N has an oxidation number of +5
In H2CO3 C has an oxidation number of +4
In CaCO3 C has an oxidation number of +4
The only oxidation- reduction reaction is <u>Cu (s) + 2AgNO3 (aq) → 2Ag (s) + Cu(NO3)2</u>
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Oxidizing agent: Ag ; Reducing agent: Cu
