Answer: The partial pressure of if the total pressure of the mixture is 3.9 atm is 0.975 atm
Explanation:
According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.
where, x = mole fraction of nitrogen in solution = 0.25
= partial pressure of nitrogen = ?
= Total pressure = 3.9 atm
Putting in the values :
The partial pressure of is 0.975 atm
Sodium becomes positively charged because it has lost an electron
The incline is frictionless, this means we can use the conservation of energy: the initial kinetic energy of the block
is converted into gravitational potential energy
where h is the height reached by the block as it stops. By equalizing the two formulas, we get
However, this is the maximum height reached by the block. The distance along the surface of the plane is given by:
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
<h3>What is the
direction of
torque?</h3>
Generally, the equation for torque is mathematically given as
τ = r X F
Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r
- We utilize our right hand.
- Place our right-hand fingers along the path of r
- Place our right-hand palm on F
- Then slowly we sweep r into F.
- The path or direction of the thumb will provide the direction of the torque.
In conclusion, the direction of this method is
D=X Option A.
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Answer:
Mass of the aluminium chunk = 278.51 g
Explanation:
For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same
A specific heat formula is given as
Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature
Q = m×c×ΔT
Heat gain by aluminium + heat lost by copper = 0 (1)
For Aluminium:
Q =
Q = m x 17.94 joule
For Copper:
Q= 4996.53 Joule
from eq 1
m x 17.94 = 4996.53
Mass of the aluminium chunk = 278.51 g