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Anna007 [38]
3 years ago
8

The intensity I of light from a light​ bulb, measured in watts per square meter ​(w/m squared​), varies inversely as the square

of the distance d from the light bulb. Suppose I is 70 ​w/m squared when the distance is 3 m. Find the intensity when the distance from the light bulb is 2 m away.?
Physics
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

157.5W/m^2

Explanation:

We are given that

I=70w/m^2

When d=3 m

We have to find the intensity when the distance from the light bulb is 2 m away.

According to question

Intensity,I\propto\frac{1}{d^2}

I=\frac{kd^2}

Where k=Proportionality constant.

Substitute the values

70=\frac{k}{3^2}

k=70\times 3^2=630

Intensity when d=2 m

I=\frac{630}{2^2}=157.5W/m^2

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Answer;

= -2.18 × 10^-5 C

Explanation;

m = 1.49 × 10^-3 kg  

Take downward direction as positive.  

Fg = m g  

E = 670 N/C  

Fe = q E  

Fe + Fg = 0  

q E + m g = 0  

q = -m g/E

   = -1.49 × 10^-3 × 9.81/670

    = -2.18 × 10^-5 C  

=  -2.18 × 10^-5 C

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Answer:

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At what distance from a long, straight wire carrying a current of 8.7 A is the magnetic field due to the wire equal to the stren
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Answer:

r= 3.2 cm

Explanation:

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We know that magnetic filed in wire at a distance r given as

B=\dfrac{\mu_oI}{2\pi r}

r=\dfrac{\mu_oI}{2\pi B}

By putting the values

r=\dfrac{1.25664\times 10^{-6}\times 8.7}{2\times \pi \times 5.4\times 10^{-5}}\ m

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Explanation:

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Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each
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Answer with Explanation:

We are given that

I_1=29 A

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d=38 cm=\frac{38}{100}=0.38 m

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