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Anna007 [38]
3 years ago
8

The intensity I of light from a light​ bulb, measured in watts per square meter ​(w/m squared​), varies inversely as the square

of the distance d from the light bulb. Suppose I is 70 ​w/m squared when the distance is 3 m. Find the intensity when the distance from the light bulb is 2 m away.?
Physics
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

157.5W/m^2

Explanation:

We are given that

I=70w/m^2

When d=3 m

We have to find the intensity when the distance from the light bulb is 2 m away.

According to question

Intensity,I\propto\frac{1}{d^2}

I=\frac{kd^2}

Where k=Proportionality constant.

Substitute the values

70=\frac{k}{3^2}

k=70\times 3^2=630

Intensity when d=2 m

I=\frac{630}{2^2}=157.5W/m^2

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Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has
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Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

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E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

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7 0
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7 0
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Calculate kinetic energy of an 86kg scooter moving at 18 m/s
myrzilka [38]

Calculate the kinetic energy of an 86-kg scooter moving at 18 m/s?

K.E.      =      (1/2)mv^2

K.E.      =        (1/2)86   *   18^2

K.E.       =         (Answer  Unit)     =====>    J

M     =      86kg

V      =        18 m/s

Significant Figures  ======>    6

Answer:   ======>   KE     =      13932 J



Show work:

1/2  *    86   *   18^2

(1/2)86  *  18^2

Remove Parenthesis:      

a        =       a

1/2 *  86  *  18^2

Multiply Fractions:

a * b/c     =    a  *  b/c

=     1  *  86  *  18^2/2

Multiply the numbers:

1  *  86     =     86

18^2    *    86/2

Divide the numbers:

86/2     =     43

18^2   *    43

18^2     =     324

43    *    324

Multiply the numbers:

43   *    324

13932

Therefore,  Your answer   is    KE    =     13932 J



Hope that helps!!!!                                   : )  sorry for the long explanation!!!








7 0
3 years ago
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