A current carrying wire is surrounded by a magnetic field. True or false

Samples of different materials, A and B, have the same mass, but the sample

Lynna [10]

Explanation:

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4 0

2 years ago

Halley’s Comet appears around the sun about once every 76 years. It passes through the part of its orbit nearest the sun in just

Scilla [17]

Answer:

There are actually three, Kepler’s laws that is, of planetary motion: 1) every planet’s orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet’s orbital period is proportional to the cube of the semi-major axis of its orbit. As it’s the third which is most often used, Kepler’s law usually means Kepler’s third law (of planetary motion).

Explanation:

Kepler's third law would tell us that Halley's comet has an average distance much greater than that of the Earth. However, there is a time in Halley's comet's orbit that brings it closer to the Sun than the Earth. Kepler's third law is a mathematical relation between a planet's period and its average distance.

4 0

3 years ago

An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c

KiRa [710]

Acceleration can be defined as the change of speed in an instant of time, that is

$a = \frac{v_f-v_i}{\Delta t}$

Here,

$v_f =$ Final velocity

$v_i =$ Initial velocity

$\Delta t =$ Change in time

From this expression we will calculate the requested values replacing the variables in each of the given terms

PART A) The values under this condition are:

$v_f = 5.3m/s$

$v_i = 15m/s$

$\Delta t = 10.4s$

Replacing,

$a = \frac{5.3m/s-(15m/s)}{10.4s}$

$a = -0.93m/s^2$

PART B ) The values under this condition are:

$v_f = -15m/s$

$v_i = -5.3m/s$

$\Delta t = 10.4$

Replacing,

$a = \frac{-(15m/s)-(-5.3m/s)}{10.4s}$

$a = -0.93m/s^2$

Therefore the acceleration in the second time interval is $-0.93m/s^2$

PART C) The values under this condition are:

$v_f = -15m/s$

$v_i = 15m/s$

$\Delta t = 10.4$

Replacing,

$a = \frac{-15m/s-(15m/s)}{10.4s}$

$a = -2.9m/s^2$

6 0

2 years ago

Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with

anastassius [24]

Answer:

2.11 m

Explanation:

Given data

h=6.626× $10^{-34\\}$ (plank constant)

L=45.7 pm

n=n2-n1

n=5-1

n=4

where,

n2=5

n1=1

To find:

E=?

λ=? (Wavelength)

solution

The energy stored in an electron at a specified level is given by;

E= $h^{2}$ × $n^{2}$ ÷8m $l^{2}$ ..........(1)

m=mass of electron(9.1× $10^{-31}$ )

l=length of box

To find E

putting the value of given data in eq(1)

E=9.41× $10^{-16}$

To find λ

λ=hc/E............................(2)

c=3× $10^{8}$ (speed of light)

putting the value in eq 2 to find wavelength

λ=2.11 m

Note:

There is a chance in calculation error. but the method is correct to solve the problem.

7 0

2 years ago

Read 2 more answers

Un tractor halando un carretón cargado con caña de azucar, viaja por el camino recto de una finca a una velocidad de 20 km/h. Si

Sidana [21]

Translation

A tractor pulling a cart loaded with sugar cane travels down the straight path of a farm at a speed of 20 km / h. If at 3:00 p.m.you pass the Finca Las Margaritas, what time will you arrive at the Las Ilusiones farm, located on the same road, if the distance between the two farms is 60 km

Answer:

6.00 pm

Explanation:

Speed is given by dividing distance by time and expressed as s=d/t. Making time the subject of the formula then t=d/s where s is the speed, d is distance covered and t is the time taken. Substituting 20 km/h for s and 60 km for d then t=60/20=3 hours

Adding 3 hours to 3 pm we get 6pm

Therefore, the time to reach the destination if the speed is constantly maintained is 6.00 pm

4 0

2 years ago