Answer:
The speed of molecules in an "ideal" gas is related to the temperature
Advanced work indicates that
1/2 m v^2 = 3/2 k T where v^2 here is the mean square speed
This is true for H2, He, O2, Hg etc. and m is the molecular mass and k the Boltzmann constant
To get the speed of light in this class glass, used the following equation
v= c/n ; where c is the speed of light in a vacuum and n where the index of refraction
Based on my research the index of refraction of the class glass is 1.59
Given
c= 3.00 x 10^8 m/s
n= 1.59
Solution
we will use 3.00 for c to get the speed of light in class glass cause 10^8 m/s is fixed
v= 3.00 / 1.59
v= 1.886
So the speed of light in this class glass is 1.89 x 10^8 m/s
The Earth heats up, the cloud coverage acting as a blanket to raise the general areas temperature.
Using SUVAT (S is displacement, U is initial Velocity, V is final velocity, A is acceleration, t is time);
S = 80m
U = 0ms^-1
V = ?
A = 9.8ms^-2
T = XXX
Use S U and A to find V;
V^2=U^2+2AS
V^2=0+2*80*9.8
V^2=1568
V=39.6ms^-1