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alexdok [17]
3 years ago
11

Which product of nuclear decay has mass but no charge?

Chemistry
1 answer:
pishuonlain [190]3 years ago
6 0
B- neutrons. Have you ever seen Jimmy neutron?
You might be interested in
Write the cell notation for an electrochemical cell consisting of an anode where Mn (s) is oxidized to Mn2 (aq) and a cathode wh
morpeh [17]

Answer:

Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

Explanation:

In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.

For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.

Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

8 0
3 years ago
Name the organic compound of ch3chohch2ch3
snow_lady [41]

Answer:

Flavouring agent 2-Butanol, or sec-butanol, is an organic compound with formula CH3CH(OH)CH2CH3.

4 0
3 years ago
why the total mass of the products would be less than the total weight of the reactant after a chemical reaction?
Lisa [10]
The best explanation would be that Gases were released during the Chemical reaction, causing a loss of Mass. 
4 0
3 years ago
An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number
igor_vitrenko [27]

Answer:

Element symbol: Kr.

Mass number: 77.

Charge : 0.

Explanation:

Hello,

In this case, since such substance has the same amount of protons and electrons we can infer it is an atom whose number of neutrons is defined by considering its atomic mass or mass number and atomic number which is actually equal to the number of protons and electrons (36):

neutrons=atomic\ mass - atomic\ number

In such a way, solving for the atomic mass we obtain:

atomic\ mass=neutrons+ atomic\ number\\\\atomic\ mass=41+36=77

It means that the element is krypton (Kr) as it has 36 electrons and protons so its charge is 0.

Best regards.

5 0
3 years ago
Calculate the number of Na ions and Cl ions and total number of ions in 14.5g of NaCl.​
Elanso [62]

Answer:

Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

Explanation:

1 mole of any compound contains 6.023 × 10²³ molecules.

molecular weight of NaCl is 23 + 35.5 = 58.5 g.

so, 58.5 grams of NaCl makes 1 mole

⇒ 14.5 g of NaCl = \frac{14.5}{58.5} =  0.248 moles.

⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules

=  1.49 × 10²³ molecules.

And 1 molecule contains 1 Na ion and 1 Cl ion.

⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

6 0
4 years ago
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