The answer is: "isotopes" .
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Answer: Velocity terminal = 0.093m/s
Explanation:
1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)
= (0.0604/2 - 0.06/2)m
= 2×10^-4
Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L
= (π×0.06×0.4)m²
= 0.075m²
Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.
Shearing stress = u×V.terminal/h = 0.86×V/0.0002
= 4300Vterminal
Therefore, Fw = shearing stress × A
30N = 4300Vterminal × 0.075
V. terminal = 30/4300 m.s
V. terminal = 0.093m/s
Answer:
The angle of recoil electron with respect to incident beam of photon is 22.90°.
Explanation:
Compton Scattering is the process of scattering of X-rays by a charge particle like electron.
The angle of the recoiling electron with respect to the incident beam is determine by the relation :
....(1)
Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant, 
is mass of electron, c is speed of light and f is the frequency of the x-ray photon.
We know that, f = c/λ ......(2)
Here λ is wavelength of x-ray photon.
Rearrange equation (1) with the help of equation (1) in terms of λ .
Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for , 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ and 134° for θ in the above equation.
= 22.90°
ANSWER:
The answer will be OT
