The answer 75.0 fam good luck
Answer:
<em>Molar mass of the gas is 0.0961 g/mol</em>
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Explanation:
The effusion rate of an unknown gas = 11.1 min
rate of effusion = 2.42 min
molar mass of hydrogen = 1 x 2 = 2 g/m
molar mas of unknown gas = ?
From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.
from
=
where
= rate of effusion of hydrogen gas
= rate of effusion of unknown gas
= molar mass of H2 gas
= molar mass of unknown gas
substituting values, we have
=
4.587 =
= /4.587
= 0.31
= = <em>0.0961 g/mol</em>
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Answer:
0.0894 M
Explanation:
So you first want to change the grams into moles (since molarity is moles solute per Liter solution).
The molar mass of NaNO3 is 84.995 g/mol, so we divide 0.38g of NaNO3 by 84.995 g/mol to get approximately 0.004471 mol NaNO3.
Now, all you have to do is to divide by the total Liters of water (your solution).
Since the volume is expressed in mL, you just need to divide by 1000 (1 L = 1000mL) to get 0.050 L solution.
Therefore, to get molarity, you divide 0.004471 mol by 0.050 L to get your answer of 0.0894 M.