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LuckyWell [14K]
3 years ago
9

Aspartame (below) is an artificial sweetener used in diet soft drinks and is marketed under many trade names, including Equal an

d Nutrasweet. In the body, aspartame is hydrolyzed to produce methanol, aspartic acid, and phenylalanine. The production of phenylalanine poses a health risk to infants born with a rare condition called phenylketonuria, which prevents phenylalanine from being digested properly. Draw the structures of aspartic acid and phenylalanine.

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer:

Find attached the structure of asparthic acid and phenylalanine

Explanation:

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Srihari has a torch with him and 2 new batteries. However, the torch requires 3 batteries to work. Is there any way Srihari can
zloy xaker [14]

Answer:

go to the store to buy more batteries

Explanation:

6 0
3 years ago
Which of the following is true for balancing equations?
nataly862011 [7]

Answer:

D) There must be equal number of atoms of each elements on both sides of equation.

Explanation:

The balancing equation must have equal number of atoms of each elements on both sides of equation.

The balance equation shoes mass is conserved thus followed the law of conservation of mas.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

In given photosynthesis reaction:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

8 0
3 years ago
 
Mashutka [201]

sodium cloride is salt created from sodium Na and chlorine Ci

Na-sodium Ca- calcium

Ci-chlorine FL- flerovium

Ca- calcium Br-bromine

H- hydrogen He-helium

6 0
3 years ago
Read 2 more answers
Do parts a, b and c
Leona [35]

Answer:- (a)The pH of the buffer solution is 3.90.

(b) the pH of the solution after addition of HCl would be 3.60.

(c) the pH of the buffer solution after addition of NaOH is 4.32.

Solution:- (a) It is a buffer solution so the pH could easily be calculated using Handerson equation:

pH=Pka+log(\frac{base}{acid})

pKa can be calculated from given Ka value as:

pKa=-logKa

pKa=-log(6.3*10^-^5)

pKa = 4.20

let's plug in the values in the Handerson equation:

pH=4.20+log(\frac{0.025}{0.05})

pH = 4.20 - 0.30

pH = 3.90

The pH of the buffer solution is 3.90.

(b) Let's say the acid is represented by HA and the base is represented by A^- .

Original mili moles of HA from part a = 0.05(100) = 5

original mili moles of A^- from part a = 0.025(100) = 2.5

mili moles of HCl that is H^+ added = 0.100(10.0) = 1

This HCl reacts with the base present in the buffer to make HA as:

A^-+H^+\rightarrow HA

Total mili moles of HA after addition of HCl = 5+1 = 6

mili moles of base after addition of HCl = 2.5-1 = 1.5

Let's plug in the values in the Handerson equation again. Here, we could use the mili moles to calculate the pH. The answer remains same even if we use the concentrations also as the final volume is same both for acid and base.

pH=4.20+log(\frac{1.5}{6})

pH = 4.20 - 0.60

pH = 3.60

So, the pH of the solution after addition of HCl would be 3.60.

(c) mili moles of NaOH or OH^- added to the original buffer = 0.05(15.0) = 0.75

This OH^- reacts with HA to form A^- as:

HA+OH^-\rightarrow H_2O+A^-

mili moles of HA after addition of NaOH = 5-0.75 = 4.25

mili moles of A^- after addition of NaOH = 2.5+0.75 = 3.25

Let's plug in the values again in Handerson equation:

pH=4.20+log(\frac{3.25}{4.25})

pH = 4.20 - 0.12

pH = 4.32

So, the pH of the buffer solution after addition of NaOH is 4.32.

7 0
3 years ago
The reaction for the burning of one type of match tip is as follows: P4S3(s) + 8 O2(g) P4O10(g) + 3 SO2(g) What volume of SO2 at
miskamm [114]

a] work out mass of 1 mole P4S3 -- call this Y grams

b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [= 3 x 22.4L at STP]  

c] by simple proportion  

1g P4S3 gives (3 x 22.4)/Y SO2 at STP answer

4 0
3 years ago
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