Answer : The molarity of solution is, 0.352 M
Explanation :
First we have to calculate the moles of
Molar mass of = 278.1 g/mol
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 1 mole of produced from 1 mole of
So, 0.07041 mole of produced from 0.07041 mole of
Now we have to calculate the molarity of
Therefore, the molarity of solution is, 0.352 M
Here is the full question:
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes? (Round your answer to three decimal places.
Answer:
0.046 %
Explanation:
The rate-in;
= 0.8
The rate-out
=
=
We can say that:
where;
A(0)= 0.2% × 6000
A(0)= 0.002 × 6000
A(0)= 12
Integration of the above linear equation =
so we have:
∴
Since A(0) = 12
Then;
Hence;
∴ the concentration at 10 minutes is ;
= %
= 0.0456667 %
= 0.046% to three decimal places
