Answer: sodium amide undergoes an acid -base reaction
Explanation:
sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.
This leads to formation of ammonia and sodium methoxide.
Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.
Hence the 3rd statement is a corrects statement.
So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.
The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.
The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.
The following reaction occurs:
NaNH₂+CH₃OH→NH₃+CH₃ONa
Answer:
in illustration 1
the mother told her son not to play with the boy having cough because it is a transferable disease which could cause him also to get sick and would get cough.
while in
illustration 2
the mother let the boy play with the boy having asthma because it is not a transferable disease which wold not affect him or any one else.
Explanation:
this is the reason
Answer:
4
Explanation:
cause 1 mole of beryllium weighs 4gram
a.
A substance's specific heat tells you how much heat is required to increase the temperature of 1 g of that substance by 1°C.
The equation that establishes a relationshop between heat and change in temperature is
q = m • c • ∆T, where
q - heat absorbed
c - the specific heat of the substance, in your case of water
ΔT - the change in temperature, defined as the difference between the final temperature and the initial temperature
so:
q = 1.00 g • 4.18 J/g×°C • (75.0 - 38.5)°C
q = 152,57 J
just apply this formula for all exercises
The standard enthalpy of formation (Δ
) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.
Standard enthalpies (Δ) of formation for given reaction is 978.3 kJ
<h3>
What is Standard enthalpies of formation?</h3>
The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.
Given reaction ;
To Find : Δ
Δ = ∑np Δ (products) – ∑np Δ (reactants)
Δ = [1(Δ 
) + 4(Δ 
)] – [1(Δ 
) + 4(Δ 
)]
Δ = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]
Δ = [4(-241.8)] – [1(+9.16)] = 978.3 kJ
Learn more about Enthalpy here ;
brainly.com/question/16720480
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