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3 years ago

What is the carrier molecule

Chemistry

2 answers:

creativ13 [48]3 years ago

6 0

Explanation:

A carrier molecule is, A role in transporting electrons through the electron transport chain carrier molecules are usually poetries bond to a non-protein group they can undergo oxidation and reduction

Aneli [31]3 years ago

6 0

Answer:

A molecule that plays a role in transporting electrons through the electron transport chain. Carrier molecules are usually proteins bound to a nonprotein group; they can undergo oxidation and reduction relatively easily, thus allowing electrons to flow through the system.

Explanation:

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A foce that pushes or pulls is known as

Radda [10]

Answer:

Newton 3rd Law of Motion or the Law of Force Pairs

(An applied force)

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3 years ago

What causes the appearance of lines in an emission spectrum?

Nikitich [7]

Answer:

key concepts and summary. When electrons move from a higher energy level to a lower one, photons are emitted, and an emission line can be seen in the spectrum. Absorption lines are seen when electrons absorb photons and move to higher energy levels

Explanation:

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3 0

3 years ago

Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH betwee

kirill115 [55]

Kc = [H3O+][HCO3-] / [H2CO3]

Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.

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2 years ago

Gas has a volume of 247.3 ML and is at 100 Celsius and 745 Hg. If the mass of the gas is 0.347 g what is the molar mass of the v

Ahat [919]

Answer:

The molar mass of the vapor is 43.83 g/mol

Explanation:

Given volume of gas = V = 247.3 mL = 0.2473 L

Temperature = T = 100 $^{\circ}C$ = 373 K

Pressure of the gas = P = 745 mmHg (1 atm = 760 mmHg)

$P = \displaystyle \frac{745}{760} \textrm{ atm} = 0.9802 \textrm{ atm}$

Mass of vapor = 0.347 g

Assuming molar mass of gas to be M g/mol

The ideal gas equation is shown below

$\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\0.98026 \textrm{ atm}\times 0.2473 \textrm{ L} = \displaystyle \frac{3.47 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 373\textrm{K} \\M = 43.834 \textrm{ g/mol}$

The molar mass of the vapor comes out to be 43.834 g/mol

4 0

3 years ago

Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of

Vlad1618 [11]

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is the number of moles of a component divided by the total number of moles in a mixture.

We must calculate the moles of each component.

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

$\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}$

2. Calculate the total moles.

$n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}$

3. Calculate the mole fraction of each component

$\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}$

6 0

3 years ago