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Alexandra [31]
3 years ago
13

An aerosol can with a temperature of 292 K and a pressure of 1.25 atm was left outside in the sun on a hot summer day. The press

ure inside the can rose to 1.33 atm. What was the resulting temperature in the can?
322K
1,600K
311K
274K

ik its not A
Chemistry
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

310.69K

Explanation:

Given parameters:

Initial temperature T₁ = 292K

Initial pressure P₁ = 1.25atm

Final pressure P₂ = 1.33atm

Unknown:

Final temperature T₂ = ?

Solution

To find the unkown, we need to apply the combined gas law. From the combined gas law, it can be deduced that at constant volume, the pressure of a give mass or mole of gas varies directly with the absolute temperature.

Since the same aerosol can is heated, the volume is constant.

          \frac{P_{1} }{T_{1} } =  \frac{P_{2} }{T_{2} }

Now, we have to make T₂ the subject of the formula:

      T₂ =  \frac{P_{2}  x T_{1}  }{P_{1} }

       T₂ =  \frac{1.33  x 292  }{1.25 } =  310.69K

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Answer both 8 and 9 will give u brain list with explanation as well so don’t just answer
goldfiish [28.3K]

Answer:

8. the answer is B.

9. the answer is A.

Explanation:

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8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.

9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:

3molO_2*\frac{2molH_2O}{1molO_2}=6molH_2O

Thus, the answer is this case is A.

Best regards!

6 0
3 years ago
Why do you require an acid catalyst to make an ester? Why not just mix acid and alcohol? Describe an alternate method of making
djverab [1.8K]

Answer:Acid catalyst is needed to increase the electrophilicity of Carbonyl group of Carboxylic acid as alcohol is a weak nucleophile.

Alternatively esters can be synthesised by converting carboxylic acid into acyl chloride using thionyl chloride(SOCl_{2} and then further treating acyl chloride with alcohol.

Carboxylic acid and esters can be easily distinguished on the basis of IR as carboxylic acid would contain a broad intense peak in 2500-3200cm_{-1} corresponding to OH stretching frequency whereas esters would not contain any such broad intense peak.

Alcohol and esters can also be distinguished using IR as alcohols would contain a broad intense peak at around 3200-3600cm_{-1}

Explanation: For the synthesis of esters using alcohol and carboxylic acid we need to add a little amount of acid in the reaction . The acid used here increases the electrophilicity of carbonyl carbon and hence makes it easier for a weaker nucleophile like alcohol to attack the carbonyl carbon of acid.

The oxygen of the carbonyl group is protonated using the acidic proton which  leads to the generation of positive charge on the oxygen. The positive charge generated is delocalised over the whole acid molecule and hence the electrophilicity of carbonyl group is increased. Kindly refer attachment for the structures.

If we simply mix the acid and alcohol then no appreciable reaction would take place between them and ester formation would not take place because the carboxylic acid in that case is not a good electrophile whereas alcohol is also not a very strong nucleophile which can attack the carbonyl group.

Alternatively we can use thionyl chloride or any other reagent which can convert the carboxylic acid into acyl chloride. Acyl chloride is very elctrophilic and alcohol can very easily attack the acyl chloride and esters could be synthesized.

The carboxylic acid and ester can very easily be distinguished on the basis of broad intense OH stretching frequency peak at around 2500-3200cm_{-1} . The broad intense OH stretching frequency peak is present in carboxylic acids as they contain OH groups and absent in case of esters .

Likewise esters and alcohols can also be distinguished on the basis IR spectra as alcohols will have broad intense spectra  at around 3200-3600cm_{-1}corresponding to OH stretching frequency whereas esters will not have any such peak. Rather esters would be having a Carbonyl stretching frequency at around 1720-1760

4 0
3 years ago
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anastassius [24]

Answer:

Glucose, found in the food animals eat, is broken down during the process of cellular respiration into an energy source called ATP. When excess ATP and glucose are present, the liver converts them into a molecule called glycogen, which is stored for later use.

4 0
3 years ago
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