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adelina 88 [10]
3 years ago
15

What hydrogen atom transitions represent emission of the longest wavelength photon?

Chemistry
2 answers:
oee [108]3 years ago
8 0
Wavelength has inverse relationship with its energy. The shorter the wavelength, the higher the energy.

Complete question was:
Which of the following transitions (in a hydrogen atom) represent emission of the longest wavelength photon?n = 1 to n = 2 <span>n = 3 to n = 1 </span>
<span>n = 3 to n = 4 </span>
<span>n = 4 to n = 2 </span>
<span>n = 5 to n = 4
</span>
The longest wavelength photon is n = 5 to n = 4. As I stated above,the wavelength and energy has inverse relationship. The longest wavelength has the lowest energy.
9966 [12]3 years ago
4 0

The correct answer is:

The longest wavelength photon is n = 5 to n = 4.

The explanation:

According to he relation between the wavelength and energy, there have inverse relationship. The longest wavelength has the lowest energy.

and when:

-Transitions to n=1 are in the UV part of the spectrum and have the shortest wavelengths.

-and Transitions to n=2 are in the visible part of the spectrum and have wavelengths between 700nm and around 400 nm

-and Transitions to n=3 or greater are in the infra-red part of the spectrum and have the longest wavelengths.

- So the longest wavelength would correspond to the lowest energy and that would correspond to the difference in energy between n=5 and n=4

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Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

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So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

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