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g100num [7]
3 years ago
11

Which answer best describes the potential energy diagram for a reaction that takes place in water, if the temperature of the sur

rounding water is lowered?
a. the potential energy of the reactants is low; the potential energy increases gradually; it peaks, then decreases slightly.

b.the potential energy of the reactants is high; the potential energy decreases gradually; then increases slightly.

c. the potential energy of the reactants is low; the potential energy remains low; rapidly peaks, then rapidly falls.

d. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.
Chemistry
2 answers:
Tanzania [10]3 years ago
7 0

Answer:

d. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.

Explanation:

Potential energy is the term that refers to the energy stored in a body, which can be used for several different things, even if transformed into other types of energy, depending on the need that that body presents at the moment. If the body needs to move, for example, the potential energy is transformed into kinetic energy. If the body needs to heat up or cool down, the potential energy turns into thermal energy.

Based on this, we can conclude what happens to the potential energy of a reaction that occurs in water, when the temperature of the surrounding water is reduced. If the temperature is reduced, it means that the water is losing energy and the potential energy of the reagents is low; as a result, the potential energy gradually decreases; then it increases a little.

blondinia [14]3 years ago
6 0
D. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.

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The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustion of
Olin [163]

Answer:

            Empirical Formula  =  C₃H₆O₁

Solution:

Data Given:

                      Mass of Ethyl Butyrate  =  3.61 mg  =  0.00361 g

                      Mass of CO₂  =  8.22 mg  =  0.00822 g

                      Mass of H₂O  =  3.35 mg  =  0.00335 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.00822 ÷ 0.00361) × (12 ÷ 44) × 100

                      %C  =  (2.277) × (12 ÷ 44) × 100

                      %C  =  2.277 × 0.2727 × 100

                      %C  =  62.09 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.00335 ÷ 0.00361) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.9279) × (2.02 ÷ 18.02) × 100

                      %H  =  0.9279 × 0.1120 × 100

                     %H  =  10.39 %


                      %O  =  100% - (%C + %H)

                      %O  =  100% - (62.09% + 10.39%)

                      %O  =  100% - 72.48%

                      %O  =  27.52 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 62.09 ÷ 12.01

                      Moles of C  =  5.169 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 10.39 ÷ 1.01

                      Moles of H  =  10.287 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 27.52 ÷ 16.0

                     Moles of O  =  1.720 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     O

             5.169                                10.287                              1.720

       5.169/1.720                       10.287/1.720                     1.720/1.720

               3.00                                   5.98                                   1

                  3                                      ≈ 6                                     1

Result:

         Empirical Formula  =  C₃H₆O₁

8 0
3 years ago
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Answer:

Removing O₂, means removing one of the reactants and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.

Explanation:

The principle that explains how changes in temperature, Concentration and Pressure of reactants or products of a reaction at equilibrium affect the equilibrium position of the reaction is the Le Chatelier's principle.

The Principle explains that a system/process if a system/process which is at equilibrium is disturbed/perturbed/constrained by one or more changes (in concentration, pressure or temperature), the system would shift the equilibrium position to counteract the effects of this change.

Removing O₂, means removing one of the reactants (changing its concentration) and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.

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iogann1982 [59]
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4 0
2 years ago
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3 years ago
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