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damaskus [11]
3 years ago
8

1. At which location does the pendulum have the least gravitational potential energy? Why?

Physics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:Point B

Explanation:When it is at the bottom of its swing (arm straight up and down). When it is at its lowest point, Gravity can not pull it down any further. This position also has the most kinetic energy because after it passes the bottom, it goes back up again and loses speed. so when the pendulum is at the bottom it is traveling the fastest it will go.

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15 m/s²

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What is the relationship between Hectare and cubic meter<br>​
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In a series RLC resonance circuit, the resonance frequency f0 = 700 kHz. The resistor R = 10 Ohm. The specified bandwidth (BW) s
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Answer:

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  • inductor = 1.591 x 10⁻⁴ H
  • capacitor = 3.248 x 10⁻¹⁰ F

Explanation:

Given;

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resistor, R =  10 Ohm

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bandwidth (BW)  = \frac{R}{2\pi L}

BW = \frac{R}{2\pi L}

make L (inductor) the subject of the formula

L = \frac{R}{2\pi *BW}  =  \frac{10}{2\pi *10,000} =1.591 *10^{-4} \ H = \ 0.1591\ mH

F_o =\frac{1}{2\pi\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi F_o} \\\\LC = \frac{1}{4\pi ^2F_o^2}= \frac{1}{4\pi ^2(700,000)^2} = 5.168*10^{-14}

make C (capacitor)  the subject of the formula

C = \frac{5.168*10^{-14}}{1.591*10^{-4}} = 3.248*10^{-10} \ F = \ 3.248*10^{-4} \ \mu F

quality factor (Q) = \frac{1}{R} \sqrt{\frac{L}{C}} \ = \frac{1}{10} \sqrt{\frac{1.591*10^{-4}}{3.248*10^{-10}}}=69.99

quality factor (Q) =  69.99

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