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k0ka [10]
3 years ago
15

- How many moles of HCl will be needed to neutralize 200.0 ml of a 2.5 M NaOH solution?

Chemistry
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

0.5 mol HCl

Explanation:

2.5 mol/L *0.200 L = 0.5 mol NaOH

                         NaOH + HCl ---> NaCl + H2O

from reaction   1 mol      1 mol

given                 0.5mol    x mol

x= 0.5*1/1= 0.5 mol HCl

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Determine the enthalpy for this reaction: Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
ivanzaharov [21]
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol

</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
    reactants                         products

products- reactants:</span><span>

(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
<span>
</span>






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