- How many moles of HCl will be needed to neutralize 200.0 ml of a 2.5 M NaOH solution?

Chemistry

1 answer:

dalvyx [7]2 years ago

4 0

Answer:

0.5 mol HCl

Explanation:

2.5 mol/L *0.200 L = 0.5 mol NaOH

NaOH + HCl ---> NaCl + H2O

from reaction 1 mol 1 mol

given 0.5mol x mol

x= 0.5*1/1= 0.5 mol HCl

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Answer:

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Explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R. T

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Answer:

1. NaN₃(s) → Na(s) + 1.5 N₂(g)

2. 79.3g

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<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>

First, we have to calculate the moles of N₂ from the ideal gas equation.

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