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Rashid [163]
3 years ago
9

What kind of charge would the hydrogen atoms have compared to the oxygen?

Chemistry
2 answers:
loris [4]3 years ago
8 0
Hydrogen would have a negative charge compared to oxygen
Mice21 [21]3 years ago
8 0
Scince water molecules are polar. unequal sharing of electrons between the elements that make it. the hydrogen atoms would experience a slight partial pisitive charge as the electron density is more close to the oxygen atom making it partially negative
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What is the name of the polyatomic in MgSO4?
blsea [12.9K]

Answer:

Magnesium Sulfate

Explanation:

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3 years ago
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Explain why the lattice energy of CaSe is approximately 4 times as large as that of KBr. Check all that apply. Check all that ap
Elza [17]

Answer:

According to Coulomb’s law, the Ca and Se ions have 4 times the attractive force (2+ × 2-) than that of the K and Br ions (1+ × 1-).

Explanation:

From Coulomb's law, the attractive force between calcium and selenium ions is four times the attractive force between potassium and bromide ions.

This has something to do with size and magnitude of charge. Calcium ions and selenide ions are smaller and both carry greater charge magnitude than potassium and bromide ions. This paves way for greater electrostatic attraction between them when the distance of the charges apart is minimal. Hence a greater lattice energy.

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3 years ago
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Explanation:

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6020000 in scientific notation
kobusy [5.1K]
6.02 x 10^6

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7 0
3 years ago
At the start of a reaction, there are 0.0249 mol N2,
gladu [14]

Answer:

Explanation:

The reaction is given as:

N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}

The reaction quotient is:

Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}

From the given information:

TO find each entity in the reaction quotient, we have:

[NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}

[N_2] = \dfrac{0.024 }{3.5}

[N_2] = 0.006857

[H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}

[H_2] = 9.17 \times 10^{-3}

∴

Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135

However; given that:

K_c = 1.2

By relating Q_c \ \ and  \ \ K_c, we will realize that Q_c \ \ <  \ \ K_c

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

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