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3 years ago

What is the name of the farthest planet away from the sun

Physics

2 answers:

Alex Ar [27]3 years ago

4 0

Answer:

It's Neptune:)

Explanation:

Igoryamba3 years ago

4 0

Answer:

Neptune is the eighth and farthest planet from the Sun, at a distance of about 4.5 billion km (2.8 billion miles) or 30.07 AU.

Explanation:

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how long would it take for a radio wave sent from a space satellite circling mars to reach Earth? Assume that radio waves (a for

kati45 [8]

Answer:

3 Minutes 2 seconds to 22 minutes 16 seconds

Explanation:

Lets assume the Mars to be at the closest distance to Earth. This distance (D) = 54.6 Million km

The signal travels at the speed of light, so speed of the signal (V) = 300000 km/s

So, the time (T) taken by the radio wave to reach Earth from Mars will be,

$T = \frac{D}{V}$

$T = \frac{54600000}{300000}$

Thus, T = 182 Sec = 3 Minutes 2 seconds.

The radio wave will take minimum 03 Minutes 02 seconds to reach Earth. Here is should be noted that the distance between the two planets keep on changing as they revolve around the Sun. There will come a point when Mars is farthest from Earth and the distance (D) will be 401 Million km. Then, the time will change to ,

$T = \frac{401000000}{300000}$

T = 1336.67 sec = 22.27 Minutes.

So the maximum time will be 22 minutes 16 seconds.

3 0

3 years ago

If you put two electrons next to each other, would they attract or repel each other? Explain your answer.

wolverine [178]

Repel, they are both negative charges, and like poles repel each other

8 0

2 years ago

Read 2 more answers

Steam at 4 MPa and 400C enters a nozzle steadily with a velocity of 60 m/s, and it leaves at 2 MPa and 300C. The inlet area of

frez [133]

Answer:

(A) 4.09 kg/s

(B) 589.9 m/s

(C) 0.0008707 m^{3} = 8.71 cm^{2}

Explanation:

inlet pressure of steam (P1) = 4 MPa

inlet temperature of steam (T1) = 400 degree celcius

inlet velocity (V1) = 60 m/s

outlet pressure (P2) = 2 MPa

outlet temperature (T2) = 300 degree celcius

inlet area (A1) = 50 cm^{2} = 0.005 m^{2}

rate of heat loss (Q) = 75 kJ/s

(A) mass flow rate (m) = \frac{A1 x V1}{α1}

where the initial specific volume (α1) for the given temperature and pressure is gotten from tables A-6 = 0.07343 m^3/kg

m = \frac{0.005 x 60}{0.07343}

m = 4.09 kg/s

(B) we can get the outlet velocity using the energy balance equation

E in = E out

m(h1 + \frac{(V1)^{2}}{2}) = m(h2 + \frac{(V2)^{2}}{2})

V2 = $\sqrt{2(h1 - h2) +(V1)^{2} - 2\frac{Q}{m}$

where h1 and h2 are the enthalpies and are gotten from table A-6

V2 = $\sqrt{2 x 1000 x(3214.5 - 3024.2) +(60)^{2} - 2\frac{75 x 1000}{4.09}$

V2 = 589.9 m/s

A2 = (α2 x m) / V2

where the initial specific volume (α2) for the given temperature and pressure is gotten from tables A-6 = 0.12552 m^3/kg

A2 = (0.12552 x 4.09) / 589.5 = 0.0008707 m^{3} = 8.71 cm^{2}

4 0

3 years ago

Do you get this ?????

Jet001 [13]

The first one is actually 10 times as big as the second one.

Because of their places, the first one means 6000, and the second one means 600.

8 0

3 years ago

A proton, moving north, enters a magnetic field. Because of this field, the proton curves downward. We may conclude that the mag

PIT_PIT [208]

Answer:

towards the west

4 0

3 years ago