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3 years ago

Think of an everyday activity where removal of one of the products helps the reaction to faster in forward direction?

Chemistry

1 answer:

elena55 [62]3 years ago

4 0

Answer:

Cooking with open, exposed flame to prevent build up of CO₂ which will extinguish the fire

Explanation:

In the cooking process whereby food is heated by the combustion of cooking gas as follows;

C₄H₁₀ (g) + (13/2)O₂ → 4CO₂(g) + 5H₂O(g), ΔH = -2658 kJ·mol⁻¹

The product of the combustion must be allowed to escape freely to allow for more reactant molecules of oxygen and butane to effectively combine.

Whereby, the CO₂ is allowed to remain and accumulate at the reaction site, the CO₂ displaces the oxygen and reduces the butane such that as the CO₂ builds up without removal, the CO₂ and butane will left in the mixture while the fire is extinguished.

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How much heat is absorbed by a 2000 g granite rock as energy from the sun causes its temperature to change from 10°C to 29°C?

emmainna [20.7K]

Answer:

None of the options are correct. The correct answer is 30020J

Explanation:

Data obtained from the question include:

Mass (M) = 2000g

Initial temperature (T1) = 10°C

Final temperature (T2) = 29°C

Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C

Heat (Q) =?

Specific heat capacity (C) of granite = 0.79J/g°C

Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:

Q = MCΔT

Q = 2000 x 0.79 x 19

Q = 30020J

3 0

3 years ago

H e l p,,, ill give brainliest :)

mote1985 [20]

Hi there! :)

Both are compounds.

$CO_{2}$ contains 1 carbon (C) atom and 2 oxygen (O) atoms.

It contains two different elements, so it is a COMPOUND.

$Na_{2} O$ is an IONIC compound with elements Sodium (Na) and Oxygen (O), which are different elements. Therefore, it is also a COMPOUND.

6 0

2 years ago

Molecules can be either positively or negatively charged depending upon their elemental arrangement

Nuetrik [128]

They are positively or negatively charged based on their electrical configuration of electrons*
For example an electronic configuration of 2,8,3 would have a negative charge if +3 since it needs to lose 3 electrons to gain the electrical configuration of a noble gas
2,8,1 would have a charge of +1 for the same reason
2,8,6 would be -2 since it is easier to gain 2 electrons that lose 6 electrons

Hope this helped :))

8 0

3 years ago

Select all that are true statements for RNA*

Kitty [74]

Answer
RNA is single stranded

6 0

3 years ago

Read 2 more answers

In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account

hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0

3 years ago

Think of an everyday activity where removal of one of the products helps the reaction to faster in forward direction?​

Think of an everyday activity where removal of one of the products helps the reaction to faster in forward direction?