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Rufina [12.5K]
2 years ago
7

How much of Earth's surface is dry, ice-free land? *

Physics
1 answer:
AleksandrR [38]2 years ago
8 0

Answer:

Less than a quarter of Earth's surfaces are dry, ice free lands

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Calculate the size of the magnetic field 20 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V
Stells [14]

Answer:

1.5 \times 10^{-5} \mathrm{~T}.

Explanation:

Power carried by the line =P=450 \mathrm{MW}=450 \times 10^{6} \mathrm{~W}

Voltage across the line Volts

Current flowing in the line =i

Size of magnetic field =B

Distance from the line

Formula Used:

Current flowing is given as

i=\frac{P}{\Delta V}

Magnetic field by the current carrying wire is given as

B=\left(\frac{\mu}{4 \pi}\right)\left(\frac{2 i}{r}\right)

Inserting the values

 B=\left(10^{-7}\right)\left(\frac{2(1500)}{(20)}\right) \\
B=1.5 \times 10^{-5} \mathrm{~T}

Conclusion:

Thus, the magnetic field comes out to be 1.5 \times 10^{-5} \mathrm{~T}.

7 0
2 years ago
Electrical conductivity in liquid solutions depends on the presence of free
Alla [95]

Answer:

electrical conductivity in liquid solutions depends on the availability of free ions.

3 0
3 years ago
A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w
ExtremeBDS [4]

Intensity of electromagnetic wave is given as

I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]

given that

I = 0.0275 W/m^2

0.0275 = \frac{B_{rms}^2}{\mu_0} \times c

here we know that

\mu_0 = 4\pi \times 10^{-7}

c = 3 \times 10^8 m/s

now we have

0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)

B_{rms} = 1.07 \times 10^{-8} T

now we will have

B_0 = \sqrt2 B_{rms}

B_0 = 1.52 \times 10^{-8} T

frequency of wave is given as

f = \frac{c}{\lambda}

f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz

now the induced EMF is given as

EMF = B_0A2\pi f

EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)

EMF = 0.0733 Volts

7 0
3 years ago
Read 2 more answers
Two cars A and B, travel in a straight line. The distance of A from the starting point is given as a function of time by x????(?
Norma-Jean [14]

Answer:

a) They are in the same point

b) t = 0 s, t = 2.27 s, t = 5.73 s

c) t = 1 s, t = 4.33 s

d) t = 2.67 s

Explanation:

Given equations are:

x_{a}(t) = at+bt^2

x_{b}(t) = ct^2-dt^3

Constants are:

a = 2.60 m/s, b = 1.20 m/s^2, c= 2.80 m/s^2, d = 0.20 m/s^3

a) "Just after leaving the starting point" means that t = 0. So, if we look the equations, both x_a(t) and x_b(t) depend on t and don't have constant terms.

So both cars A and B are in the same point.

b) Firstly, they are in the same point in x = 0 at t = 0. But for generalized case, we must equalize equations and solve quadratic equation where roots will give us proper t value(s).

at+bt^2 = ct^2-dt^3

2.6t + 1.2t^2 = 2.8t^2 - 0.2t^3\\0.2t^2 - 1.6t + 2.6 = 0\\t^2 - 8t + 13 = 0

t_1 = 4 - \sqrt{3} = 2.27 s, t_1 = 4 + \sqrt{3} = 5.73 s

c) Since the distance isn't changing, the velocities are equal. To find velocities, we need to take the derivatives of both equations with respect to time and equalize them.

v_a(t) = \frac{d}{d(t)}x_a(t) = a + 2bt \\v_b(t) = \frac{d}{d(t)}x_b(t) = 2ct - 3dt^2\\a+2bt = 2ct - 3dt^2\\3dt^2+2(b-c)t+a = 0\\0.6t^2-3.2t+2.6 = 0

t_1 = 1 s, t_2 = 4.33 s

d) For same acceleration, we we need to take the derivatives of velocity equations with respect to time and equalize them.

a_a(t) = \frac{d}{d(t)}v_a(t) = 2b \\a_b(t) = \frac{d}{d(t)}v_b(t) = 2c - 6dt\\2b = 2c - 6dt\\3dt = c - b\\t = (c - b)/3d = (2.8 - 1.2)/(3*0.2) = 2.67 s

3 0
3 years ago
Read 2 more answers
Riders on a ferris wheel move in a circle with a speed of 4.0 m/s. As they go around, they
Vanyuwa [196]
Answer: D = 16m

Explanation: given values: a = 2 m/s2, v = 4 m/s
In this case we have to determine the diameter of the Ferris wheel.
Diameter of circle is given as: D = 2.r.
First we have to find radius of wheel. The best way to find that is using the centripetal acceleration equation: a = v2/r
Plug in values in above equation to find radius: 2 m/s2 = (4 m/s)2/r 2 m/s2 = (16 m2/s2)/r r = (16 m2/s2)/2 m/s2
r = 8.0m
Diameter of Ferris wheel is:
D = 2.r.
D = 2.8m
D = 16m
6 0
3 years ago
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