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3 years ago

A person covers a distance of 320 miles in a travel time of 8 hours. What is the speed for this trip?

Physics

2 answers:

goldfiish [28.3K]3 years ago

8 0

Take 320 and divide by 8
320/8 = 40 mi/hr or A

sasho [114]3 years ago

3 0

It would be A, 40 miles per hour.

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Bright white shadings on infrared images indicate cloud tops that have relatively ________ temperatures

Maru [420]

Infrared is created by detecting the produced radiation coming off of clouds. The temperature of the cloud will define the wavelength of radiation produced from the cloud. The benefit of the infrared imagery is that can be used day and night to conclude the temperature of the cloud tops and earth surface structures and to get the general idea of how clouds are. Based on the general guidelines to define cloud features, if the cloud is bright white on infrared then it is a high cloud or has a cloud top that is developed high into the troposphere. In this way infrared images actually display patterns of temperature on a gray scale such that at one extreme dark gray is warm and at the other extreme bright white is cold. A color scale is used to portray temperature and some improved infrared images show two or more gray scale sequences. High cold clouds are brighter white than low warm clouds.

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3 years ago

At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak

Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

$P = AI$

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

$A = \frac{\pi d^2}{4}$

Now the intensity is inversely proportional to the square of the distance from the source, then

$I \propto \frac{1}{r^2}$

The expression for the intensity at different distance is

$\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}$

Here,

$I_1$ = Intensity at distance 1

$I_2$ = Intensity at distance 2

$r_1$ = Distance 1 from light source

$r_2$ = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

$I_2 = I_1 (\frac{r_1^2}{r_2^2})$

If we replace with our values at this equation we have,

$I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})$

$I_2 = 1.11*10^{-4} W/m^2$

Now using the equation to find the area we have that

$A = \frac{\pi (8.4*10^{-3}m)^2}{4}$

$A = 5.5*10^{-5}m^2$

Finally with the intensity and the area we can find the sound power, which is

$P = AI$

$P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)$

$P = 6.1*10^{-9}J/s$

Power is defined as the quantity of Energy per second, then

$E = 6.1*10^{-9}J$

8 0

3 years ago

Can someone please help me with science.

kherson [118]

Answer:

Yes

Explanation:

5 0

3 years ago

Read 2 more answers

If a frictional force of 4 N is acting against a push of 53 N and the box that is being pushed is 4 kg, what is its acceleration

kifflom [539]

Answer:

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Explanation:

3 0

3 years ago

Calculate the normal force pushing up from the table in each example 8 kg

garik1379 [7]

The correct answer to the question is: 78.4 N.

EXPLANATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the normal force of the object.

The object is resting on the table.

Hence, the object pushes the table downward with a force equal to it's weight.

The table, in turn, pushes the object with the same force as given by the object, but in the upward direction.

The force given by the table on the object is known as the normal reaction of the object which acts perpendicular to the surface of the object.

Hence, the normal reaction is equal to the weight of the body.

The weight of a body is the product of it's mass with acceleration due to gravity.

So, the weight of 8 Kg object is calculated as -

Weight = mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the normal force pushing up from the table is 78.4 N.

8 0

3 years ago