Nothing flammable of explosive type of material is around
Answer:
0.71 lbf
Explanation:
Use ideal gas law:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
The absolute pressure is the sum of the atmospheric pressure and the gauge pressure.
P = 32 lbf/in² + 14.7 lbf/in²
P = 46.7 lbf/in²
Absolute temperature is in Kelvin or Rankine:
T = 75 + 459.67 R
T = 534.67 R
Given V = 3.0 ft³, and R = 10.731 ft³ psi / R / lb-mol:
PV = nRT
(46.7 lbf/in²) (3.0 ft³) = n (10.731 ft³ psi / R / lb-mol) (534.67 R)
n = 0.02442 lb-mol
The molar mass of air is 29 lbm/lb-mol, so the mass is:
m = (0.02442 lb-mol) (29 lbm/lb-mol)
m = 0.708 lbm
The weight of 1 lbm is lbf.
W = 0.708 lbf
Rounded to two significant figures, the weight of the air is 0.71 lbf.
Answer:
We know that all petrol engines are works on Otto cycle.Otto cycle have four process out of four two are constant volume process and others two are isentropic processes.
There are lots of limitations for practical Otto cycle these are as follows
1.In practical cycle heat can not add at constant volume.
2.In practical cycle there is a gap between combustion of two set of fuel.
3.Lots of heat is dissipated by cylinders.
4.Valve opening and closing is not a sudden process it requires some time.
5.There is a limitations of cylinder material ,it means that temperature of cycle can not rise after a specified limit of material.
Due to these above limitations practical cycles have low efficiency as compare to ideal cycle.
A54545 is the thing which is your
Explanation:
Answer:
The detailed answer to the question is explained in the attached file.
Explanation:
