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xenn [34]
2 years ago
8

chan hee is inflating a basketball using an air pump. he notices that the pump gets warm as he uses it. what is a good hypothesi

s that could lead to new experimentation?
Chemistry
2 answers:
PtichkaEL [24]2 years ago
8 0

Explanation:

When air is inflated into the basket ball then it means pump which is the system becomes warm.

Since work is done by the system and when pump is compressed then we are increasing pressure on air molecules inside it. Therefore, they will gain kinetic energy and this energy will be released in the form of heat.

Due to which the pump becomes warm.

Thus, we can conclude that a good hypothesis that could lead to new experimentation is that temperature of the pump is increased.

juin [17]2 years ago
3 0
I hypothesize that compressing air causes the temperature to increase.
Can you give me a brainliest?
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The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:
Elina [12.6K]

\huge \underbrace \mathfrak \red{Answer}

28%

Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

\sf \large {mass \: percentage =  \frac{mass \: of \: solute}{mass \: of \: solvent}  \times 100} \\  \\  \sf  mass \: percentage =  \frac{3.73}{134.73}  \times 100 \\  \\  \sf mass \: percentage =  0.028 \times 100 \\  \\  \sf mass \: percentage = 28\%

7 0
2 years ago
if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is
svet-max [94.6K]

Answer:

               The volume is increased.

Explanation:

                     According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

                                                    V₁ / T₁ = V₂ / T₂   -----(1)

In statement the data given is,

T₁  =  10 °C  =  283.15 K                    ∴  K  =  273.15 + °C

T₂  =  20 °C  =  293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁  =  100 L

V₂  =  Unknown

Now, we will arrange equation 1 for V₂ as,

                                                    V₂  =  V₁ × T₂ / T₁

Putting values,

                                     V₂  = 100 L × 293.15 K / 283.15 K

                                     V₂  = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0
3 years ago
A system gains 652 kJ of heat, resulting in a change in internal energy of the system equal to +241 kJ. How much work is done?
levacccp [35]

Answer:

-411 kj

Explanation:

We solve by using this formula

∆U = ∆Q + ∆W

This formula is the first law of thermodynamics

Change in internal energy U = +241

Heat gained by system Q = 652

Putting the value into the equation

+241 = 652 + W

Workdone = 241 - 652

Workdone = -411 kj

Since work done is negative it means that work was done by the system

3 0
2 years ago
Identify 3 items that are malleable
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Some examples of malleable materials are gold, silver, iron, aluminum, copper and tin.
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Which criteria determine whether a heterogeneous mixture is a colloid or a suspension
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<span>whether the particles do not settle for an extended period of time</span>
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