1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xenn [34]
3 years ago
8

chan hee is inflating a basketball using an air pump. he notices that the pump gets warm as he uses it. what is a good hypothesi

s that could lead to new experimentation?
Chemistry
2 answers:
PtichkaEL [24]3 years ago
8 0

Explanation:

When air is inflated into the basket ball then it means pump which is the system becomes warm.

Since work is done by the system and when pump is compressed then we are increasing pressure on air molecules inside it. Therefore, they will gain kinetic energy and this energy will be released in the form of heat.

Due to which the pump becomes warm.

Thus, we can conclude that a good hypothesis that could lead to new experimentation is that temperature of the pump is increased.

juin [17]3 years ago
3 0
I hypothesize that compressing air causes the temperature to increase.
Can you give me a brainliest?
You might be interested in
Why is very important to wait until the crucible is fully coleed to room temperature before weighting
Mars2501 [29]

If you do not wait until the crucible is at room temperature, its density will vary constantly until it reaches this temperature, since density is a property that varies with temperature. For the above reason, weighing a hot crucible will not allow the measurement of a constant weight on the balance, since <u>the weight of the object will be constantly changing, which will not allow a constant reading.</u>

3 0
3 years ago
Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s
disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid.  HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R   HSO_4^-    ⇄  H^+ + SO_4^2^-

I    0.14

C   - x               +x       +x

E   0.14-x        x         x

K_a = 1.3 × 10^-^2 for HSO^-_4 . As a result,

\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a

K_a is large. It is no longer valid to approximate that [HSO^-_4] at equilibrium is the same as its initial value.

\frac{x^2}{0.14-y} = 1.3 * 10^-^2

x^2+1.3*10^-^2x - 0.14 × 1.3 × 10^-^2= 0

Solving the quadratic equation for x , x \geq 0 since x represents a concentration;

                             x=0.0366538

Then, round the results to 2 significant figure;

  • [SO_4^2^-] = x = 0.037 mol. L ^-^1
  • [H^+] = x = 0.037 mol. L ^-^1
  • [HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1

Learn more about concentration here:

brainly.com/question/14469428

#SPJ4

3 0
2 years ago
Rutherford's experiments on atoms were done on foil made of which of the following elements?
AnnyKZ [126]
A. Gold

Gold is the answer
7 0
3 years ago
Read 2 more answers
A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio
myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

W = -P*(V_{2} - V_{1})

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K);  R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

V_{1} is the initial volume = 0.350 L

V_{2} is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*(V_{2} - 0.350) L

V_{2} = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

7 0
3 years ago
Which element is found in all the acids described in this section?
mixer [17]
Acids contain hydrogen!
8 0
3 years ago
Other questions:
  • All biochemical pathways have the same number of enzymatic reactions <br> a. True <br> b. False.
    12·1 answer
  • Explain oxidation and reduction occur simultaneously​
    9·2 answers
  • The weight of a cup filled with water is 2.58kg The weight of the empty cup is 1.5 kg. Considering significant figures what is w
    7·1 answer
  • Which is a strong base? HCl NaOH NH3 H3CO3
    8·1 answer
  • Predict whether a precipitation reaction will occur when aqueous solutions of pbcl2 and (nh4)2s
    11·1 answer
  • A gas sample has a volume of 222 mL at 55.0 °C and 100.0 kPa pressure. Find the volume at
    8·1 answer
  • What is the final temperature of a system if 10.0 grams of cold water, originally at 10°C is mixed with 120.0 grams of hot water
    13·1 answer
  • If I have 7.7 moles of gas at a pressure of 9.12 kPa and a temperature of 56 °C,
    8·1 answer
  • Calculate how many moles of silver nitrate (AgNO3) are in 1.35 L of a 4.25 M solution of silver
    14·1 answer
  • Which describes a property of water that allows plants to transfer it from their roots to their leaves? Water exhibits weak adhe
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!