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xenn [34]
3 years ago
8

chan hee is inflating a basketball using an air pump. he notices that the pump gets warm as he uses it. what is a good hypothesi

s that could lead to new experimentation?
Chemistry
2 answers:
PtichkaEL [24]3 years ago
8 0

Explanation:

When air is inflated into the basket ball then it means pump which is the system becomes warm.

Since work is done by the system and when pump is compressed then we are increasing pressure on air molecules inside it. Therefore, they will gain kinetic energy and this energy will be released in the form of heat.

Due to which the pump becomes warm.

Thus, we can conclude that a good hypothesis that could lead to new experimentation is that temperature of the pump is increased.

juin [17]3 years ago
3 0
I hypothesize that compressing air causes the temperature to increase.
Can you give me a brainliest?
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How do you decide which conversion factor to use?
Juliette [100K]

Answer:

When a conversion is necessary, the appropriate conversion factor to an equal value must be used. For example, to convert inches to feet, the appropriate conversion value is 12 inches equal 1 foot. To convert minutes to hours, the appropriate conversion value is 60 minutes equal 1 hour

Explanation:

hope this helps have a good night/day :) ❤

8 0
3 years ago
A 100.00 ml of volume of 0.500 M HCl was mixed with 100.00 ml of 0.500 M KOH in a constant pressure calorimeter. The initial tem
Virty [35]

Answer:

The heat of the reaction = -1985 J = -1.985 kJ

The enthalpy of the reaction is -39.7 kJ/ mol

Explanation:

<u>Step 1: </u>Data given

Volume of HCl = 100 mL the heat of the reaction = 0.1 L

Molarity of HCl solution = 0.500 M

Volume of KOH = 100 mL = 0.1 L

Molarity of KOH solution = 0.500 M

Initial temperature = 23.0 °C

Final temperature = 25.5 °C

Specific heat of the solution = 3.97 J/°C *g

Density of the solution = 1g/ mL

<u>Step 2: </u>Calculate heat

Q = m*c*ΔT

with m = the mass of both solution : 100g + 100 g ( since density = 1g/mL) = 200 g

c = the specific heat = 3.97 J/°C*g

ΔT  = T2 -T1 = 25.5 = 23 = 2.5 °C

Q = 200g *3.97 J/°C*g * 2.5°C = 1985 J  (= -1985 J because it's exothermic)

<u />

<u>Step 3:</u> Calculate the number of moles

Number of moles = Molarity * Volume

Number of moles = 0.5 * 0.1 L = 0.05 moles

(Moles of the acid are equal to the moles of water produced.

Moles of solution = 0.05 moles)

<u>Step 4: </u>Calculate the enthalpy of the reaction

ΔH = heat change /Number of moles

    = -1.985 kJ/ 0.05 moles

   =- 39700 J/mol = -39.7 kJ/ mol

The enthalpy of the reaction is -39.7 kJ/ mol

The enthalpy of the reaction is negative, this means the reaction is exothermic ( which means the final temperature is higher than the initial temperature.)

7 0
4 years ago
Mars is known as the ____ planet.<br><br> A) Blue<br> B) Gaseous<br> C) Red<br> D) Sandy
Leni [432]

Answer:

Of course it's C

Red planet

Explanation:

It is because the soil on Mars is rich of Fe (Iron).

That makes the soil look red.

Even on our planet we have such this places like hormuz island in Iran.

5 0
3 years ago
PLEASE HELP ME SOLVE THIS.Thank you so much!
Tju [1.3M]

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}

Now, the two half-reactions can be written as follows.

Reduction half-reaction: Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}

This will be balanced as follows.

Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O ... (1)

Oxidation half-reaction: Cl^{-} \rightarrow Cl_{2} + 1e^{-}

This will be balanced as follows.

6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-} ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

6 0
3 years ago
What are the three physical properties of gases
daser333 [38]
They are described through the use of four physical properties or macroscopic characteristics: pressure, volume, number of particles (chemists group them by moles) and temperature.
5 0
3 years ago
Read 2 more answers
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