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Minchanka [31]
3 years ago
12

When a 4-kg ball is thrown upwards at 40 m/s, at what

Physics
1 answer:
arlik [135]3 years ago
4 0

Answer:

the height of the potential energy is 3,200 J

Explanation:

The computation of the kinetic energy is shown below:

Kinetic energy = 1 ÷ 2 × mass × velocity^2

= 1 ÷ 2 × 4 kg × 40 m/s^2

= 3,200 J

Hence the height of the potential energy is 3,200 J

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What should be the indication on the magnetic compass as you roll into a standard rate turn to the right from a northerly headin
lapo4ka [179]

Answer:

The compass will indicate a turn to the left.

Explanation:

The magnetic compass has a needle pointing towards north. It is used for navigation and it shows direction with respect to the geographical cardinal direction.

As we move to the right of the northerly heading in northern Hemisphere, the direction of needle will move towards left but with a faster rate as now the direction of north is no his left.

This shows the compass if following its direction properly.

4 0
3 years ago
What patterns are caused by the Earth, Sun, and Moon systems?
MatroZZZ [7]

Answer: Solor cycles and tings

5 0
3 years ago
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Which of the following graph is used for determining the instantaneous velocity from the slope?
hoa [83]

Answer:

B. x - t graph

Explanation:

A position-time (x-t) graph is a graph of the position of an object against (versus) time.

Generally, the slope of the line of a position-time (x-t) graph is typically used to determine or calculate the velocity of an object.

An instantaneous velocity can be defined as the rate of change in position of an object in motion for a short-specified interval of time. Thus, an instantaneous velocity is a quantity that can be found by measuring the slope of a line that is tangent to a point on the graph.

Hence, the x - t graph also referred to as the position-time graph is used for determining the instantaneous velocity from the slope.

<u>For example;</u>

Given that the equation of motion is S(t) = 4t² + 2t + 10. Find the instantaneous velocity at t = 5 seconds.

Solution.

S(t) = 4t^{2} + 2t + 10

Differentiating the equation, we have;

S(t) = 8t + 2

Substituting the value of "t" into the equation, we have;

S(5) = 8(5) + 2

S(5) = 40 + 2

S(5) = 42 m/s.

5 0
3 years ago
Read 2 more answers
Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr
Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

W = dP + dK\\

Where

dP = Change in Potential Energy

dK = Change in Kinetic Energy

Change in Potential Energy

P_{i} = mgh_{i}\\  P_{f} = mgh_{f}

Where

P_{i} = Initial Potential Energy

P_{f} = Final Potential Energy

m = Mass of System = 10,000 kg

g = Acceleration due to gravity = 9.81 m/s

h_{i} = Initial Height = 0

h_{f} = Final Height = 30 m

Inputting the values we get the answer for dP

dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000

Change in Kinetic Energy

K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2

Where

K_{i} = Initial Kinetic Energy

K_{f} = Final Kinetic Energy

m = Mass of System = 10,000 kg

g = Acceleration due to gravity = 9.81 m/s

v_{i} = Initial Velocity = 0 m/2

v_{f} = Final Velocity = 4 m/s

Inputting the values we get the answer for dK

dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000

Total Work

W = dP + dK\\

Inputting the values

W = 2943000 + 80000

W = 3,023,000

a) Finding the useful Power Output

P = \frac{W}{t}

Where

P = Power Output

W = Work Done = 3,023,000J

t = Time = 12s

Inputting the values

P = \frac{3,023,000}{12}\\ P = 251,916.667

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0
3 years ago
4. How does density affect refraction of a lightwave?
Brums [2.3K]

optical density would increase the refraction angle going in to the material

there may be a relation between opt density and mass density ... kg/m^3

7 0
3 years ago
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