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Mashutka [201]
3 years ago
15

A circular coil comprised of N = 180 closely wrapped turns of wire and has a radius R = 0.55 m. A counterclockwise current I = 3

.4 A is in the coil. The coil is set in a magnetic field of magnitude B = 1.1 T. The magnetic field points to right. What is the potential energy of the coil in the magnetic field, in terms of the variables provided?
Physics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

U = 0 J

Explanation:

Given

N = 180

R = 0.55 m

Iy = 3.4 A

Bx = 1.1 T

U = ?

We can apply the following equation:

U = - μtotal*B*Cos ∅

where

μtotal = N*I*A = N*I*(π*R²) = 180*3.4 A*(π*(0.55 m)²)

⇒   μtotal = 581.603 A*m²

then

U = - (581.603 A*m²)*(1.1 T)*Cos 90º = 0 J

as we know ∅ = 90º

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2 years ago
A bullet is shot horizontally from shoulder height (1.5 m) with an initial speed 200 m/s. (a) How much time elapses before the b
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Answer:

<h2>a) Time elapsed before the bullet hits the ground is 0.553 seconds.</h2><h2>b) The bullet travels horizontally 110.6 m</h2>

Explanation:

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We have equation of motion s = ut + 0.5 at²

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        Acceleration, a = 9.81 m/s²  

        Displacement, s = 1.5 m      

     Substituting

                      s = ut + 0.5 at²

                      1.5 = 0 x t + 0.5 x 9.81 xt²

                      t = 0.553 s

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b) Consider the horizontal motion of bullet

We have equation of motion s = ut + 0.5 at²

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                      s = ut + 0.5 at²

                      s = 200 x 0.553 + 0.5 x 0 x 0.553²

                      s = 110.6 m

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