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3 years ago

An element that is unable to create a ion and therefore always has a charge of 0 is most likely a member of a family called

Physics

1 answer:

Allisa [31]3 years ago

7 0

Explanation:

'noble gases' which are also known as group VIII

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A child pushes a toy car down a hill. The child has a mass of 20 kg. The car has a mass of 1.6 kg and a speed of 7.4 m/s2. When

Andrew [12]

Answer:

The answer is 73.8 J

Explanation:

5 0

3 years ago

The x vector component of a displacement vector has a magnitude of 86.2 m and points along the negative x axis. The y vector com

Flauer [41]

Answer:

(a) Magnitude of Vector = 207.73 m

(b) Direction = 65.48°

Explanation:

(a)

The formula to find out the magnitude of a resultant vector with the help of its x and y components is given as follows:

$Magnitude\ of\ Vector = \sqrt{d_{x}^{2} + d_{y}^{2}} = \sqrt{(86.2\ m)^{2} + (189\ m)^{2}}\\\\$

<u>Magnitude of Vector = 207.73 m</u>

(b)

For the direction of the vector we have the formula:

$Direction = tan^{-1}(\frac{y}{x})\\\\Direction = tan^{-1}(\frac{189\ m}{86.2\ m})\\\\$

<u>Direction = 65.48°</u>

4 0

3 years ago

DEFINA O QUE É AGILIDADE?

faltersainse [42]

Answer:

sorry

Explanation:

sorry lol i don't know

3 0

3 years ago

Read 2 more answers

An action force and its reaction force are:

Soloha48 [4]

Answer:

b. equal in size and opposite in direction

6 0

3 years ago

Read 2 more answers

A 0.145-kg baseball pitched horizontally at 35.0 m/s strikes a bat and is popped straight up to a height of 40.0m. If the contac

Nookie1986 [14]

Answer:

$F = 2.6 \times 10^3 N$

Explanation:

Maximum height reached by the ball after being popped by the bat is given as

$y = 40 m$

now we know by energy conservation final speed of the ball after being hit by the bat is given as

$\frac{1}{2}mv^2 = mgh$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.81)(40)}$

$v = 28 m/s$

now the change in momentum of the ball is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.145(28\hat j + 35 \hat i)$

now force is given as rate of change in momentum

$F = \frac{\Delta P}{\Delta t}$

$F = \frac{0.145(28\hat j + 35 \hat i)}{2.5 \times 10^{-3}}$

$F = (1.62 \hat j + 2.03 \hat i)\times 10^3 N$

so magnitude of the force is given as

$F = \sqrt{1.62^2 + 2.03^2} \times 10^3 N$

$F = 2.6 \times 10^3 N$

4 0

3 years ago