Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s ). If a particular disk is spun at 470.2 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

Answer:

826.36203 m/s²

Explanation:

$\omega_f$ = Final angular velocity = 470.2 rad/s

$\omega_i$ = Final angular velocity = 0

$\alpha$ = Angular acceleration

t = Time taken

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-470.2}{0.569}\\\Rightarrow a=-826.36203\ m/s^2$

Magnitude of the average angular acceleration of the disk is 826.36203 m/s²