26. Classify each chemical equation as a combination/synthesis , decomposition, single replacement, double replacement, or combu
stion.
a. Pb(s) + Hg2SO4(s) PbSO4(s) +2 Hg(l)
b. NaCl(aq) + AgNO3(aq) AgCl(s) + NaNO3(aq)
c. 2 H20(l)2 H2(g) + 02(g)
27. Find the molar mass of nitric acid (HNO3).
28. Avogadro’s number refers to ___.
a. the maximum number of electrons that all of an atom’s energy levels can accommodate
b. the number of protons and neutrons that can fit in the shells of an atom’s nucleus
c. the number of particles in one mole of a substance
d. the number of particles in exactly 1.0 g of a substance
29. How many moles of oxygen atoms are in 1.5 moles of CO2? (Sc2c)
a. 1 mol b. 1.5 mol c. 2 mol d. 3 mol
30. What is the mass of 0.28 mol of iron ?
a. Pb(s) + Hg2SO4(s) PbSO4(s) +2 Hg(l)
b. NaCl(aq) + AgNO3(aq) AgCl(s) + NaNO3(aq)
c. 2 H20(l)2 H2(g) + 02(g)
27. Find the molar mass of nitric acid (HNO3).
28. Avogadro’s number refers to ___.
a. the maximum number of electrons that all of an atom’s energy levels can accommodate
b. the number of protons and neutrons that can fit in the shells of an atom’s nucleus
c. the number of particles in one mole of a substance
d. the number of particles in exactly 1.0 g of a substance
29. How many moles of oxygen atoms are in 1.5 moles of CO2? (Sc2c)
a. 1 mol b. 1.5 mol c. 2 mol d. 3 mol
30. What is the mass of 0.28 mol of iron ?
1 answer:
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Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.
Hence, moles of =
.......... (1)
As, No. of moles =
Hence, moles of will be calculated as follows.
No. of moles =
= (molar mass of
is 255.415 g/mol)
=
Moles of =
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity =
=
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.