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taurus [48]
3 years ago
8

26. Classify each chemical equation as a combination/synthesis , decomposition, single replacement, double replacement, or combu

stion.
a. Pb(s) + Hg2SO4(s)  PbSO4(s) +2 Hg(l)
b. NaCl(aq) + AgNO3(aq)  AgCl(s) + NaNO3(aq)
c. 2 H20(l)2 H2(g) + 02(g)



27. Find the molar mass of nitric acid (HNO3).

28. Avogadro’s number refers to ___.
a. the maximum number of electrons that all of an atom’s energy levels can accommodate
b. the number of protons and neutrons that can fit in the shells of an atom’s nucleus
c. the number of particles in one mole of a substance
d. the number of particles in exactly 1.0 g of a substance


29. How many moles of oxygen atoms are in 1.5 moles of CO2? (Sc2c)
a. 1 mol b. 1.5 mol c. 2 mol d. 3 mol

30. What is the mass of 0.28 mol of iron ?

Chemistry
1 answer:
Natali [406]3 years ago
8 0

These are the answers.


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PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS
julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

8 0
3 years ago
Which is the state of matter shown in this figure ?
Veronika [31]

Answer:

Solid

Explanation:

The particles are densely packed and in a defined shape, therefore they would be defined as a solid.

5 0
3 years ago
Read 2 more answers
Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(
anygoal [31]

<em>K</em> = 2.4 × 10^(-72)

<em>Step 1</em>. Determine the <em>value of n </em>

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ <em>n</em> = 2

<em>Step 2</em>. Calculate <em>K</em>

log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)

8 0
3 years ago
4. Write down the differentiate between a. Atom and molecules​
andre [41]

Answer:

Atoms are single neutral particles. Molecules are neutral particles made of two or more atoms bonded together.

Explanation:

Atom refers to the smallest constituent unit of a chemical element. Molecules refer to a group of two or more atoms that are held together due to chemical bonds.

7 0
3 years ago
Read 2 more answers
Which property of waves is the distance between one point on a wave and that same point on the wave next to it?
mr Goodwill [35]
The answer is B, wavelength
4 0
3 years ago
Read 2 more answers
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