Answer:
the image is virtual and erect and the lens divergent; therefore the correct answer is C
Explanation:
In a thin lens the magnification given by
m = h '/ h = - q / p
where h ’is the height of the image, h is the height of the object, q is the distance to the image and p is the distance to the object.
It indicates that the object is straight and is placed at a distance p> f
analyze the situation tells us that the magnification is positive so the distance to the image must be negative, that is, that the image is on the same side as the object.
Consequently the lens must be divergent
The magnification value is
0.4 = h ’/ h
h ’= 0.4 h
therefore the erect images
therefore the image is virtual and erect and the lens divergent; therefore the correct answer is C
Answer:
Height, h = 10.20 meters
Explanation:
It is given that,
Mass of the object, m = 3 kg
Energy of object, E = 300 J
Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :



h = 10.20 meters
So, the object will move to height of 10.20 meters. Hence, this is the required solution.
Answer
given,
range of the projectile = 4.3 m
time of flight = T = 0.829 s


v = 5.19 m/s
vertical component of velocity of projectile
v_y = gt'



a) Launch angle


θ = 38°
b) initial speed of projectile


v = 6.59 m/s
c) maximum height reached by the projectile



Answer:
B. Landscape B
Explanation:
Shale is fine sediment pressed together to form rock.
Sandstone is larger (sand-grain-sized) sediment cemented together to form rock.
Shale erodes faster, as evidenced by the second attachment. That attachment shows erosion of a rock face consisting of interbedded shale and sandstone. The shale has receded significantly, leaving the sandstone layers with space between them.