1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
luda_lava [24]
3 years ago
11

How high up is a 3 kg object that has 300 joules of energy

Physics
2 answers:
BaLLatris [955]3 years ago
6 0
You use the Work Formula
W=F*d
or W=mgh
So W = 300 J
m= 3kg
g = 9.8
an d you have to find h
so 300 = 3*9.8*h
h=10.2m
kvasek [131]3 years ago
5 0

Answer:

Height, h = 10.20 meters

Explanation:

It is given that,

Mass of the object, m = 3 kg

Energy of object, E = 300 J

Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :

E=mgh

h=\dfrac{E}{mg}

h=\dfrac{300\ J}{3\ kg\times 9.8\ m/s^2}

h = 10.20 meters

So, the object will move to height of 10.20 meters. Hence, this is the required solution.

You might be interested in
The force that keeps objects moving in a circle is called centrifugal force.<br> True<br> False
Doss [256]

Answer: False

Explanation:

3 0
3 years ago
Read 2 more answers
Definition of graph?
xeze [42]

<u>Answer:</u>

1. A graph is defined as <em>" A Diagram represents a system of connections or interrelations among two or more things by a number of different dots, lines etc".</em>

2. In simple words <em>"Graph is a representation of any object or a physical structure by dots, lines, etc.</em>

6 0
3 years ago
At 5.0 minutes, the temperature of the water reaches 100 °C. The volume of the water in the urn
serious [3.7K]

Answer:

fdvevddvevkejokef0jeovdlvkjeuiyv

Explanation:

ddf4edscd

4 0
3 years ago
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
S_A_V [24]

Answer:

Given:

Thermal Kinetic Energy of an electron, KE_{t} = \frac{3}{2}k_{b}T

k_{b} = 1.38\times 10^{- 23} J/k = Boltzmann's constant

Temperature, T = 1800 K

Solution:

Now, to calculate the de-Broglie wavelength of the electron, \lambda_{e}:

\lambda_{e} = \frac{h}{p_{e}}

\lambda_{e} = \frac{h}{m_{e}{v_{e}}              (1)

where

h = Planck's constant = 6.626\times 10^{- 34}m^{2}kg/s

p_{e} = momentum of an electron

v_{e} = velocity of an electron

m_{e} = 9.1\times 10_{- 31} kg = mass of electon

Now,

Kinetic energy of an electron = thermal kinetic energy

\frac{1}{2}m_{e}v_{e}^{2} = \frac{3}{2}k_{b}T

}v_{e} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{e}}}

}v_{e} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{9.1\times 10_{- 31}}}

v_{e} = 2.86\times 10^{5} m/s                    (2)

Using eqn (2) in (1):

\lambda_{e} = \frac{6.626\times 10^{- 34}}{9.1\times 10_{- 31}\times 2.86\times 10^{5}} = 2.55 nm

Now, to calculate the de-Broglie wavelength of proton, \lambda_{e}:

\lambda_{p} = \frac{h}{p_{p}}

\lambda_{p} = \frac{h}{m_{p}{v_{p}}                             (3)

where

m_{p} = 1.6726\times 10_{- 27} kg = mass of proton

v_{p} = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T

}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}

}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}

v_{p} = 6.674\times 10^{3} m/s                               (4)                    

Using eqn (4) in (3):

\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm

7 0
3 years ago
At an air show, a stunt pilot performs a vertical loop-the-loop in a circle of radius 3.63 x 103 m. During this performance the
san4es73 [151]

Answer:

189 m/s

Explanation:

The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.

So, F = W

mv²/r = mg

v² = gr

v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m

So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

v = √(3.5574 × 10⁴ m²/s²)

v = 1.89 × 10² m/s

v = 189 m/s

5 0
3 years ago
Other questions:
  • Do you think copper would have oxidized of it was completly submerged in vinigar
    6·1 answer
  • Two identical objects are moving directly toward one another at the same speed v. ~v −~v m m What is the total kinetic energy of
    15·2 answers
  • Which of the following terms relate to the meaning of "physical"?
    11·2 answers
  • Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the
    10·1 answer
  • Which scientist first discovered that white light is a mixture of a rainbow spectrum of light rays?
    15·2 answers
  • In an electrochemical cell, the anode is ____.
    14·1 answer
  • Explain why sublimation and deposition are classified as physical changes
    13·1 answer
  • What are the names of neptunes moons
    5·1 answer
  • ABC Corporation paid an executive $300,000.00 in annual compensation. A state court determines that this compensation was excess
    6·1 answer
  • Which particles in an atom could demonstrate that opposite charges attract?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!