Answer:
his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.
determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.
a)0.7956kg/s
b)5.437 × 10⁻³m²
Explanation:
The concepts related to the change of mass flow for both entry and exit is applied
The general formula is defined by

Where,

values are divided by inlet(1) and outlet(2) by


PART A) Applying the flow equation

PART B) For the exit area we need to arrange the equation in function of Area, that is

The steps<span> of the </span>scientific method<span> are to: Ask a Question. Do Background Research. Construct a Hypothesis. Test Your Hypothesis by Doing an Experiment. Analyze Your Data and Draw a Conclusion.</span>
Explanation:
u = 0m/s
v = 30m/s
a = 2m/s²
Using Kinematics, we have v = u + at.
Therefore t = (v - u) / a
= (30 - 0) / (2) = 15 seconds. (B)
Answer:
put the car on fire
Explanation:
if you put it on fire you would have a lot of light now
Answer:
290
Explanation:
Average acceleration is the change in velocity over change in time.
First, find the velocity by taking the derivative of position.
v(t) = dx/dt
v(t) = 38t + 21t²
At t = 3 and t = 9:
v(3) = 303
v(9) = 2043
So the average acceleration is:
a = Δv / Δt
a = (2043 − 303) / (9 − 3)
a = 290
Use appropriate units.