<h2>Electrostatic Potential Decreases</h2>
Explanation:
- If the spacing between two closely spaced oppositely charged parallel plates is decreased the electrostatic potential difference between the plates will decrease.
- An electrostatic potential that is also referred to as the electric field potential or potential drop is the amount of work required to replace a unit of charge from a reference point to a specific point inside the electric field without any change in acceleration.
- Therefore, if the distance will decrease between oppositely charged plates there will be more affinity to attract which will reduce the amount of work done thus decreasing the electric potential
∴ The Correct option is (b)
Answer:
velocity of the metal cylinder = 0.343 m/s
Explanation:
Force putting the metal cylinder is given by
F = mv²/r
But this force will balance the frictional force between the metal cylinder and the turntable
The frictional force is given by
μN = μ × mg = 0.08 × 0.2 × 9.81 = 0.15696 N
r = 0.15 m, m = 0.2 kg,
F = mv²/r = 0.2 v²/(0.15) = 1.3333 v²
1.3333 v² = 0.15696
v² = 0.117
v = 0.343 m/s
The angular frequency of the cyclotron is 0.07 x
Hz.
<h3>What is angular frequency?</h3>
- Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
- It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>
The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.
<h3>Calculation of angular frequency:</h3>
Given,
B = 0.47 T
r = 0.68
mass of proton = 1.6x
q = 1.6 x 
so, the frequency is:
f = qB/2
m
f = 1.6 x
x 0.47/2x3.14x1.6x
f = 0.07 x 
Hence, the angular frequency of the cyclotron is 0.07 x
Hz.
Learn more about angular frequency here:
brainly.com/question/14244057
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Answer:
Magnetic field, B = 0.042 T
Explanation:
It is given that,
Speed of charged particle, 
Angle between velocity and the magnetic field, 
Charge, 
Magnetic force, F = 0.002 N
The magnetic force is given by :

B is the magnetic field


B = 0.042 T
So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.