1. HCl (H:1, Cl 35.5) ---> 1+35.5 = 36.5
2. FeS (Fe:56, S:32) ---> 56+32 = 88
3. Cl2 (Cl:35.5) ---> 35.5 x 2 = 71
4. CaC03 (Ca:40, C: 12, O: 16) ---> 40 + 12 + 3(16) = 100
5. Fe0 (Fe: 56, O: 16) ---> 56+16=72
Answer:
butyne
Explanation:
alkane, alkene, and alkyne are all examples of hydrocarbons.
butyne = alkyne
The correct answer is species
The answer is
2Ag+(aq) + SO4-2(aq) → Ag2SO4(s)
<span>NO3- and K+ ions are spectators </span>
