Answer:
7923.6 g of (NH₄)₂SO₄ can be produced by this reaction
Explanation:
The reaction is:
2NH₃ (aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
In this reaction ratio is 1:1.
As the ammonia is in excess, the limiting reagent is the sulfuric acid.
So 1 mol of sulfuric can produce 1 mol of sulfate
Then, 60 moles of sulfuric must produce 60 moles of sulfate.
We convert the moles to mass:
60 mol . 132.06 g / 1mol = 7923.6 g
Lithium is the Alkali metal
Answer:
A precipitate will be formed
Explanation:
The Ksp equilibrium of Fe(OH)₃ is:
Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)
And its expression is:
Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³
<em>Where the concentrations are concentrations in molarity in equilibrium,</em>
We can write Q as:
Q = [Fe³⁺] [OH⁻]³
<em>Where [] are actual concentrations in molarity of each specie.</em>
<em />
When Q>= Ksp; a precipitate is formed,
When Q< Ksp no precipitate is produced:
[OH⁻] = [NaOH] = 1.0x10⁻⁴M
[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M
<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>
<em />
Q = [Fe³⁺] [OH⁻]³
Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³
Q = 3.8x10⁻¹⁵
As Q >> Ksp; A precipitate will be formed
