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elixir [45]
3 years ago
13

Which of the following is likely to be true about the ΔH for this reaction?

Chemistry
2 answers:
Juliette [100K]3 years ago
7 0
I would say A.

Because it is cooling down, going from liquid to solid, so it is loosing energy. THis energy must be being released to the surroundings so 
olya-2409 [2.1K]3 years ago
6 0

Answer: Option (a) is the correct answer.

Explanation:

Enthalpy is defined as the total amount of heat present in a system.

When there is bond formation in a chemical reaction then it means energy is released. Hence, the reaction is exothermic in nature and \Delta H < 0 or negative.

On the other hand, when breaking of bonds occurs then energy is absorbed by the system. Hence, the reaction is endothermic in nature and \Delta H > 0 or positive.

Thus, in the given reaction C_{6}H_{6}(l) \rightarrow C_{6}H_{6}(s), the state is changing from liquid to solid.

This means atoms are coming close to each other and hence, there is occurrence of bond formation. As a result, energy will be released to the surroundings.

Hence, we can conclude that H < 0 for the given reaction.

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Oxygen is participating in non-polar covalent bond(s)

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This is because oxygen atoms have 6 valence electrons. This means that it has 2 lone pairs and 2 unpaired electrons that are shared in order to achieve octet configuration.

In this chemistry, the 2 lone pairs on the oxygen are not shared with any other atoms. Instead; they are assigned to the oxygen atom. The formal charge on the oxygen atom is zero. Oxygen's atomic number is 8 and is equal to the sum of the number of its valence and inner shell electrons.

<h3>What is non-polar covalent bonding?</h3>

Nonpolar covalent bonding is a kind of covalent bond in which the bonding electrons are shared equally between the two atoms.

Learn more about non-polar covalent bonding:

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